使用JSON.NET从JSON中获取值

Question

我试图使用http://www.codeplex.com/Json从JSON对象中提取值。

我使用imdbapi.com，它们返回的JSON如下：

{"Title": "Star Wars", "Year": "1977", "Rated", "PG", "Released", "25 May 1977", "Genre", "Action, Adventure, Fantasy, Sci-Fi "" Director ":" George Lucas "," Writer "," George Lucas "," Actors ":" Mark Hamill, Harrison Ford, Carrie Fisher, Alec Guinness, "" Plot ":" Luke Skywalker leaves his home planet, teams up With Other Rebels, and Tries to save Princess Leia from the evil clutch of Darth hrs 1 min "," Rating ":" 8.8 "," Votes ":" 397318 "," ID ":" tt0076759 "," Response ":" True "}

如何获取电影的标题、评分和年份信息，并将其保存到对象中？

这行代码返回正确的 JSON：

JObject jObject = JObject.Parse (json);

现在我只需要帮忙挑选我想要的数据。有什么建议吗？

- SteelSoft

Answer 1

这应该会对你有所帮助：http://james.newtonking.com/pages/json-net.aspx

string json = @"{
    ""Name"": ""Apple"",
    ""Expiry"": new Date(1230422400000),
    ""Price"": 3.99,
    ""Sizes"": [
        ""Small"",
        ""Medium"",
        ""Large""
    ]
}";

JObject o = JObject.Parse(json);

//This will be "Apple"
string name = (string)o["Name"];

- ThePrimeagen

---

你应该测试一下这个键是否存在：o.ContainsKey("Name")。 - Mo Zaatar

Answer 2

JObject API文档

我认为您对返回JTokens的.Item[key]集合感兴趣。

完整文档

- Abdul Hfuda

Answer 3

class TypeHere{
   string Name {get;set;}
}

TypeHere object = JsonConvert.DeserializeObject< TypeHere >(jsonString)

// Ex. output 
object.Name;

- Sean Zamora