我有一个可用的虚函数add
,它使用以下设置:
using Func = std::function<std::vector<unsigned char>()>;
class cfExecutor {
public:
cfExecutor();
virtual ~cfExecutor();
/// Enqueue a function to be executed by this executor. This and all
/// variants must be threadsafe.
virtual void add(Func) = 0;
virtual void add(std::vector<Variant> params, Func callback) = 0;
};
class ManualExecutor : public cfExecutor
{
std::mutex lock_; // avoid multiple entity updating the function container
std::queue<Func> funcs_; // functions queued for running
public:
std::map<int8_t, Func> funcs; // Function container (priority,Func) - added functions to this Executors
ManualExecutor() {}
ManualExecutor(ManualExecutor&& other):
funcs(std::move(other.funcs))
{}
~ManualExecutor() {}
void add(Func callback);
void add(std::vector<Variant> params, Func callback);
};
我想给这个函数添加可变参数,就像这样:
using Func = std::function<std::vector<unsigned char>(const auto&...args)>;
然而,我遇到了隐式错误[隐式模板可能不是“虚拟的”]
我应该如何定义具有可变参数的add函数?
到目前为止,我使用以下方法解决了这个问题:
using Func = std::function<std::vector<unsigned char>(std::vector<Variant>)>;
然后让lambda函数从内部向量处理接收参数 - 就像这样:
auto lambdaFunction = [](std::vector<Variant> vec){
std::vector<unsigned char> result;
cout << "- Hello from executor - lambdaFunction ";
std::cout << ": parameters : ";
for(auto a: vec) {
std::cout << a << ",";
}
std::cout << std::endl;
std::string s("this is the result");
result.insert(result.end(),s.begin(), s.end());
return result;
};
auto ...
时,Func
不是一个具体类型。你需要将其作为模板别名,如下所示:template<typename ... Ts> using Func = std::function<xyz(Ts const & ...)>;
- Nawaz