我该如何使用Google Maps JavaScript API v3解析反向地理编码的响应?
这在弹出窗口中显示格式化的地址很好,但我试图从响应中取出其他部分,理想情况下是街道名称或路线(如果没有找到街道名称)。但是当使用
geocoder.geocode({'latLng': latlng}, function(results, status) {
if (status == google.maps.GeocoderStatus.OK) {
if (results[0]) {
infowindow.setContent(results[0].formatted_address);
infowindow.open(map, marker);
}
}
这在弹出窗口中显示格式化的地址很好,但我试图从响应中取出其他部分,理想情况下是街道名称或路线(如果没有找到街道名称)。但是当使用
obj = JSON.parse(json);
时,我一直在控制台中收到此错误。
SyntaxError: JSON.parse:意外字符
如果是PHP,我会做很多 for each
循环。在JavaScript中是否可以做类似的操作?
这是一个示例:
{
"results" : [
{
"address_components" : [
{
"long_name" : "131",
"short_name" : "131",
"types" : [ "street_number" ]
},
{
"long_name" : "Stubbington Avenue",
"short_name" : "Stubbington Ave",
"types" : [ "route" ]
},
{
"long_name" : "Portsmouth",
"short_name" : "Portsmouth",
"types" : [ "locality", "political" ]
},
{
"long_name" : "Portsmouth",
"short_name" : "Portsmouth",
"types" : [ "administrative_area_level_3", "political" ]
},
{
"long_name" : "Portsmouth",
"short_name" : "Portsmouth",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "England",
"short_name" : "England",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "United Kingdom",
"short_name" : "GB",
"types" : [ "country", "political" ]
},
{
"long_name" : "PO2",
"short_name" : "PO2",
"types" : [ "postal_code_prefix", "postal_code" ]
},
{
"long_name" : "Portsmouth",
"short_name" : "Portsmouth",
"types" : [ "postal_town" ]
}
],
"formatted_address" : "131 Stubbington Avenue, Portsmouth PO2, UK",
"geometry" : {
"location" : {
"lat" : 50.8170795,
"lng" : -1.0709701
},
"location_type" : "ROOFTOP",
"viewport" : {
"northeast" : {
"lat" : 50.81842848029149,
"lng" : -1.069621119708498
},
"southwest" : {
"lat" : 50.8157305197085,
"lng" : -1.072319080291502
}
}
},
"types" : [ "street_address" ]
}
],
"status" : "OK"
}
这是我的开发页面链接,其中包含我的完整代码。
简而言之,我如何从上面的混乱中获得“Stubbington Avenue”?
[object][object]
等内容,我是不是没有正确传递它?obj = JSON.parse(results);
- Rudiger Kidd