这是一个学校项目;我遇到了很多麻烦,而且似乎找不到易懂的解决方案。
a b c d e z
a - 2 3 - - -
b 2 - - 5 2 -
c 3 - - - 5 -
d - 5 - - 1 2
e - 2 5 1 - 4
z - - - 2 4 -
那是一个二维数组。所以如果你想找到最短的路径,从a、b、e、d、z=7和(a,b)=(b,a)开始——它会带你到新的行来寻找该行相邻的路径。
有人能帮我实现Dijkstra算法吗?我真的很感激。(我似乎更喜欢使用数组,映射和集合让我有点困惑,列表是可以管理的——虽然我愿意研究任何解决方案)
[至少我不只是从网上抄袭源代码。我真的想学这些东西......只是真的很难(>_<)]
哦,起点是A,终点是Z
像大多数人一样,我并不觉得算法的概念难——我只是无法正确编写代码......请帮帮我?
示例代码——一个朋友帮了我很多忙(虽然它充满了我难以理解的数据结构),我还试图将从dreamincode.net/forums/blog/martyr2/index.php?showentry=578的C++代码改编成Java,但那并不顺利...
import java.util.*;
public class Pathy{
private static class pathyNode{
public final String name;
public Map<pathyNode, Integer> adjacentNodes;
public pathyNode(String n){
name = n;
adjacentNodes = new HashMap<pathyNode, Integer>();
}
}
//instance variables
//constructors
//accessors
//methods
public static ArrayList<pathyNode> convert(int[][] inMatrix){
ArrayList<pathyNode> nodeList = new ArrayList<pathyNode>();
for(int i = 0; i < inMatrix.length; i++){
nodeList.add(new pathyNode("" + i));
}
for(int i = 0; i < inMatrix.length; i++){
for(int j = 0; j < inMatrix[i].length; j++){
if(inMatrix[i][j] != -1){
nodeList.get(i).adjacentNodes.put(nodeList.get(j),
new Integer(inMatrix[i][j]));
}
}
}
return nodeList;
}
public static Map<pathyNode, Integer> Dijkstra(ArrayList<pathyNode> inGraph){
Set<pathyNode> visited = new HashSet<pathyNode>();
visited.add(inGraph.get(0));
pathyNode source = inGraph.get(0);
Map answer = new TreeMap<pathyNode, Integer>();
for(pathyNode node : inGraph){
dijkstraHelper(visited, 0, source, node);
answer.put(node, dijkstraHelper(visited, 0, source, node));
}
return answer;
}
private static int dijkstraHelper(Set<pathyNode> visited, int sum, pathyNode start, pathyNode destination){
Map<pathyNode, Integer> adjacent = new HashMap<pathyNode, Integer>();
for(pathyNode n : visited){
for(pathyNode m: n.adjacentNodes.keySet()){
if(adjacent.containsKey(m)){
Integer temp = n.adjacentNodes.get(m);
if(temp < adjacent.get(m)){
adjacent.put(m, temp);
}
}
else{
adjacent.put(m, n.adjacentNodes.get(m));
}
}
}
Map<pathyNode, Integer> adjacent2 = new HashMap<pathyNode, Integer>();
Set<pathyNode> tempSet = adjacent.keySet();
tempSet.removeAll(visited);
for(pathyNode n: tempSet){
adjacent2.put(n, adjacent.get(n));
}
adjacent = adjacent2;
Integer min = new Integer(java.lang.Integer.MAX_VALUE);
pathyNode minNode = null;
for(pathyNode n: adjacent.keySet()){
Integer temp = adjacent.get(n);
if(temp < min){
min = temp;
minNode = n;
}
}
visited.add(minNode);
sum += min.intValue();
sum = dijkstraHelper(visited, sum, start, destination);
return sum;
}
//main
public static void main(String[] args){
int[][] input = new int[][] { {-1, 2, 3, -1, -1, -1},
{2, -1, -1, 5, 2, -1},
{3, -1, -1, -1, 5, -1},
{-1, 5, -1, -1, 1, 2},
{-1, 2, 5, 1, -1, 4},
{-1, -1, -1, 2, 4, -1},
};
//-1 represents an non-existant path
System.out.println(Dijkstra(convert(input)));
}
}