我试图进行以下两个整数的除法:
variable m0Low : integer := 0;
variable m1Low : integer := 0;
m1Low := divide(m1Low,m0Low);
使用该函数:
function divide (a : UNSIGNED; b : UNSIGNED) return UNSIGNED is
variable a1 : unsigned(a'length-1 downto 0):=a;
variable b1 : unsigned(b'length-1 downto 0):=b;
variable p1 : unsigned(b'length downto 0):= (others => '0');
variable i : integer:=0;
begin
for i in 0 to b'length-1 loop
p1(b'length-1 downto 1) := p1(b'length-2 downto 0);
p1(0) := a1(a'length-1);
a1(a'length-1 downto 1) := a1(a'length-2 downto 0);
p1 := p1-b1;
if(p1(b'length-1) ='1') then
a1(0) :='0';
p1 := p1+b1;
else
a1(0) :='1';
end if;
end loop;
return a1;
end divide;
然而,我收到以下错误:
在此上下文中,除法不能具有这样的操作数。
我试图将变量转换为无符号 m1Low := divide(unsigned(m1Low),unsigned(m0Low));
但我得到以下错误:
表达式无法转换为类型 unsigned。
有什么想法吗?
谢谢
哈里斯
m1Low := M1Low/m0Low
? - Martin Thompson