你好,
我有以下代码来从当前的AD创建树:
public static ActiveDirectory GetActiveDirectoryTree(string pathToAD = "")
{
DirectoryEntry objADAM = default(DirectoryEntry);
// Binding object.
DirectoryEntry objGroupEntry = default(DirectoryEntry);
// Group Results.
DirectorySearcher objSearchADAM = default(DirectorySearcher);
// Search object.
SearchResultCollection objSearchResults = default(SearchResultCollection);
// Binding path.
ActiveDirectory result = new ActiveDirectory();
ActiveDirectoryItem treeNode;
// Get the AD LDS object.
try
{
if (pathToAD.Length > 0)
objADAM = new DirectoryEntry();
else
objADAM = new DirectoryEntry(pathToAD);
objADAM.RefreshCache();
}
catch (Exception e)
{
throw e;
}
// Get search object, specify filter and scope,
// perform search.
try
{
objSearchADAM = new DirectorySearcher(objADAM);
objSearchADAM.Filter = "(&(objectClass=group))";
objSearchADAM.SearchScope = SearchScope.Subtree;
objSearchResults = objSearchADAM.FindAll();
}
catch (Exception e)
{
throw e;
}
// Enumerate groups
try
{
if (objSearchResults.Count != 0)
{
//SearchResult objResult = default(SearchResult);
foreach (SearchResult objResult in objSearchResults)
{
objGroupEntry = objResult.GetDirectoryEntry();
result.ActiveDirectoryTree.Add(new ActiveDirectoryItem() { Id = objGroupEntry.Guid, ParentId = objGroupEntry.Parent.Guid, AccountName = objGroupEntry.Name, Type = ActiveDirectoryType.Group, PickableNode = false });
foreach (object child in objGroupEntry.Properties["member"])
{
treeNode = new ActiveDirectoryItem();
var path = "LDAP://" + child.ToString().Replace("/", "\\/");
using (var memberEntry = new DirectoryEntry(path))
{
if (memberEntry.Properties.Contains("sAMAccountName") && memberEntry.Properties.Contains("objectSid"))
{
treeNode.Id = Guid.NewGuid();
treeNode.ParentId = objGroupEntry.Guid;
treeNode.AccountName = memberEntry.Properties["sAMAccountName"][0].ToString();
treeNode.Type = ActiveDirectoryType.User;
treeNode.PickableNode = true;
treeNode.FullName = memberEntry.Properties["Name"][0].ToString();
byte[] sidBytes = (byte[])memberEntry.Properties["objectSid"][0];
treeNode.ObjectSid = new System.Security.Principal.SecurityIdentifier(sidBytes, 0).ToString();
result.ActiveDirectoryTree.Add(treeNode);
}
}
}
}
}
else
{
throw new Exception("No groups found");
}
}
catch (Exception e)
{
throw new Exception(e.Message);
}
return result;
}
问题在于使用 (var memberEntry = new DirectoryEntry(path)) 返回 DomainUsers 作为此树的用户,我不确定这是否正确?
假设我存储了 DomainUsers 节点的 sidId,然后将其发送到以下方法:
public static Boolean GetActiveDirectoryName(string sidId,out string samAccountName,out string fullName)
{
samAccountName = string.Empty;
fullName = string.Empty;
if (sidId != null && sidId.Length > 0)
{
var ctx = new System.DirectoryServices.AccountManagement.PrincipalContext(ContextType.Domain, null);
using (var up = UserPrincipal.FindByIdentity(ctx, IdentityType.Sid, sidId))
{
samAccountName = up.SamAccountName;
fullName = up.Name;
return true;
}
}
return false;
}
up将被设置为null吗?如果我选择AD中的另一个用户,那么它就可以正常工作。我怀疑DomainUsers是一个组,但我该如何在DirectoryEntry上检查这个组?
最好的问候
group
是正确的返回值,container
是用于组织单位的,这是 MSDN 示例中显示的内容。 - Maverik