在C#中播放音频字节数组

Question

我知道在C#中可以使用SoundPlayer播放声音;然而，我想通过这种方法使用操作系统默认的声音播放器播放从字节数组表示的声音。这可能吗？

- Mani5556

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你的 byte[] 的来源是什么？是 wav 还是其他什么？ - abatishchev

Answer 1

SoundPlayer构造函数接受一个Stream以播放。您可以通过创建MemoryStream从byte[]中获取Stream。

- SoftMemes

Answer 2

使用应用程序打开任何文件，例如媒体播放器，都需要一个文件。

因此，您需要将字节数组以某种格式（例如WAV）保存到文件中，并打开它：

byte[] bytes = ...
string name = Path.ChangeExtension(Path.GetRandomFileName(), ".wav");
string path = Path.Combine(Path.GetTempPath(), name);
File.WriteAllBytes(path, bytes);
Process.Start(path);

这段代码将打开用户默认的媒体播放器，就像在Windows资源管理器中单击它一样。

- abatishchev

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好的，我也有这个猜测！谢谢。 - Mani5556

Answer 3

abatishchev给出了一个很好的答案，但是你不需要将字节保存到文件中再播放文件。你可以将这些字节写入MemoryStream，然后像这个方法一样播放MemoryStream：

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Windows.Forms;

public static void PlayBeep(UInt16 frequency, int msDuration, UInt16 volume = 16383)
{
    var mStrm = new MemoryStream();
    BinaryWriter writer = new BinaryWriter(mStrm);

    const double TAU = 2 * Math.PI;
    int formatChunkSize = 16;
    int headerSize = 8;
    short formatType = 1;
    short tracks = 1;
    int samplesPerSecond = 44100;
    short bitsPerSample = 16;
    short frameSize = (short)(tracks * ((bitsPerSample + 7) / 8));
    int bytesPerSecond = samplesPerSecond * frameSize;
    int waveSize = 4;
    int samples = (int)((decimal)samplesPerSecond * msDuration / 1000);
    int dataChunkSize = samples * frameSize;
    int fileSize = waveSize + headerSize + formatChunkSize + headerSize + dataChunkSize;
    // var encoding = new System.Text.UTF8Encoding();
    writer.Write(0x46464952); // = encoding.GetBytes("RIFF")
    writer.Write(fileSize);
    writer.Write(0x45564157); // = encoding.GetBytes("WAVE")
    writer.Write(0x20746D66); // = encoding.GetBytes("fmt ")
    writer.Write(formatChunkSize);
    writer.Write(formatType);
    writer.Write(tracks);
    writer.Write(samplesPerSecond);
    writer.Write(bytesPerSecond);
    writer.Write(frameSize);
    writer.Write(bitsPerSample);
    writer.Write(0x61746164); // = encoding.GetBytes("data")
    writer.Write(dataChunkSize);
    {
        double theta = frequency * TAU / (double)samplesPerSecond;
        // 'volume' is UInt16 with range 0 thru Uint16.MaxValue ( = 65 535)
        // we need 'amp' to have the range of 0 thru Int16.MaxValue ( = 32 767)
        double amp = volume >> 2; // so we simply set amp = volume / 2
        for (int step = 0; step < samples; step++)
        {
            short s = (short)(amp * Math.Sin(theta * (double)step));
            writer.Write(s);
        }
    }

    mStrm.Seek(0, SeekOrigin.Begin);
    new System.Media.SoundPlayer(mStrm).Play();
    writer.Close();
    mStrm.Close();
} // public static void PlayBeep(UInt16 frequency, int msDuration, UInt16 volume = 16383)

针对你的问题，你不需要这个方法中大部分创建WAV格式字节流的代码，但是你可以使用方法末尾的技巧来避免将字节保存到文件中。

- Shawn Kovac

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如果你只是复制并粘贴显然不是你自己的代码而没有提及原始作者，你应该感到羞耻... 给你-1分（原始答案在这里https://dev59.com/OXVC5IYBdhLWcg3wtzoQ#19772815） - Markus Safar

Answer 4

尝试从如何从数组中播放。

PlayerEx pl = new PlayerEx();

private static void PlayArray(PlayerEx pl)
{
    double fs = 8000; // sample freq
    double freq = 1000; // desired tone
    short[] mySound = new short[4000];
    for (int i = 0; i < 4000; i++)
    {
        double t = (double)i / fs; // current time
        mySound[i] = (short)(Math.Cos(t * freq) * (short.MaxValue));
    }
    IntPtr format = AudioCompressionManager.GetPcmFormat(1, 16, (int)fs);
    pl.OpenPlayer(format);
    byte[] mySoundByte = new byte[mySound.Length * 2];
    Buffer.BlockCopy(mySound, 0, mySoundByte, 0, mySoundByte.Length);
    pl.AddData(mySoundByte);
    pl.StartPlay();
}

- Aleks