我使用Boost程序选项库来解析命令行参数。
我的要求如下:
- 一旦提供了“help”选项,则所有其他选项都是可选的;
- 一旦未提供“help”选项,则所有其他选项都是必需的。
我该如何处理这个问题?以下是我处理此问题的代码,但我发现它非常冗长,我认为一定有更简单的方法,对吗?
#include <boost/program_options.hpp>
#include <iostream>
#include <sstream>
namespace po = boost::program_options;
bool process_command_line(int argc, char** argv,
std::string& host,
std::string& port,
std::string& configDir)
{
int iport;
try
{
po::options_description desc("Program Usage", 1024, 512);
desc.add_options()
("help", "produce help message")
("host,h", po::value<std::string>(&host), "set the host server")
("port,p", po::value<int>(&iport), "set the server port")
("config,c", po::value<std::string>(&configDir), "set the config path")
;
po::variables_map vm;
po::store(po::parse_command_line(argc, argv, desc), vm);
po::notify(vm);
if (vm.count("help"))
{
std::cout << desc << "\n";
return false;
}
// There must be an easy way to handle the relationship between the
// option "help" and "host"-"port"-"config"
if (vm.count("host"))
{
std::cout << "host: " << vm["host"].as<std::string>() << "\n";
}
else
{
std::cout << "\"host\" is required!" << "\n";
return false;
}
if (vm.count("port"))
{
std::cout << "port: " << vm["port"].as<int>() << "\n";
}
else
{
std::cout << "\"port\" is required!" << "\n";
return false;
}
if (vm.count("config"))
{
std::cout << "config: " << vm["config"].as<std::string>() << "\n";
}
else
{
std::cout << "\"config\" is required!" << "\n";
return false;
}
}
catch(std::exception& e)
{
std::cerr << "Error: " << e.what() << "\n";
return false;
}
catch(...)
{
std::cerr << "Unknown error!" << "\n";
return false;
}
std::stringstream ss;
ss << iport;
port = ss.str();
return true;
}
int main(int argc, char** argv)
{
std::string host;
std::string port;
std::string configDir;
bool result = process_command_line(argc, argv, host, port, configDir);
if (!result)
return 1;
// Do the main routine here
}