如果WiFi名称匹配，Android如何以编程方式连接WiFi

Question

我希望建立一个应用程序，可以检查所有可用的WiFi网络。如果一个网络的SSID与搜索关键字匹配，则连接到该网络；如果有两个网络匹配，则连接信号强度更高的那个网络。例如，搜索关键字为“Open”；以下是检查所有WiFi名称的代码：

    if (networkInfo.isConnected()) {
                ArrayList<ScanResult> mItems = new ArrayList<ScanResult>();
            List<ScanResult> results = wifiManager.getScanResults();
            int size  = results.size();
            HashMap<String, Integer> signalStrength = new HashMap<String, Integer>();
            try {
                for (int i = 0; i < size; i++) {
                    ScanResult result = results.get(i);
                    if (!result.SSID.isEmpty()) {
                        String key = result.SSID + " " + result.capabilities;
                        Log.i("TAG", "ssid: " + result.SSID + " | level: " + result.level);
}

然后我需要执行以下操作：

Arrays.asList(mItems).contains("Open")

我被困在这里，如何正确检查关键字“Open”是否存在，如果存在，则获取整个名称并使用以下方法？

在线样例如何连接。

WifiConfiguration wifiConfig = new WifiConfiguration();
wifiConfig.SSID = String.format("\"%s\"", ssid);
wifiConfig.preSharedKey = String.format("\"%s\"", key);

WifiManager wifiManager = (WifiManager).getSystemService(WIFI_SERVICE);
//remember id
int netId = wifiManager.addNetwork(wifiConfig);
wifiManager.disconnect();
wifiManager.enableNetwork(netId, true);
wifiManager.reconnect();

更新代码 ------------------------------- - --------------------------------- - -- ---------------------------------------

如何检查，这部分代码已经可用，但现在我需要实现按信号强度搜索

if (!result.SSID.isEmpty()) {
                        String key = result.SSID + " " + result.capabilities;
                        Log.i("TAG", "ssid: " + result.SSID + " | level: " + result.level);


                        if(result.SSID.contains("Open")) {
                            String useSSID = result.SSID;
                            Log.w(TAG, "useSSID => " + useSSID);

                            connectToWifi(MainActivity.this, useSSID);
                            break;
                        }
                        else { Log.e(TAG, "NO result  contains"); }

现在我该如何查询我的：

ArrayList<ScanResult> mItems = new ArrayList<ScanResult>();


                if (!signalStrength.containsKey(key)) {
                    signalStrength.put(key, i);
                    mItems.add(result);
                } else {
                    int position = signalStrength.get(key);
                    ScanResult updateItem = mItems.get(position);
                    if (calculateSignalStength(wifiManager, updateItem.level) > calculateSignalStength(wifiManager, result.level)) {
                        mItems.set(position, updateItem);
                    }
                }


                     if(mItems.contains("Open")) {
                                String useSSID = mItems #how to the name SSID name from mItems ???
                                Log.w(TAG, "useSSID => " + useSSID);

                                connectToWifi(MainActivity.this, useSSID);
                                break;
                            }
                            else { Log.e(TAG, "NO result  contains"); }

=== 我的问题是如何从mItems中获取SSID名称？ 感谢大家的帮助。

- Thiago

---

如果（result.SSID.contains("Open")） - user253751

我不理解这部分代码 - 如果 (!result.SSID.isEmpty()) {如果 (result.SSID.contains("Open")) {useSSID = 如何获取包含“Open”的完整SSID} - Thiago

嗨，感谢您的帮助。我已经更新了我的问题并附上了代码。 - Thiago

Answer 1

以下是相应的代码段：

这里是同样的片段：

public string getValidSSID()
{
    List<ScanResult> results = wifiManager.getScanResults();
    HashMap<String,ScanResult> distinctNetworks = new HashMap<String, ScanResult>();
    for(ScanResult scanResult :  results)
    {
        if(scanResult.SSID.contains("Open"))
        {
            if(!distinctNetworks.containsKey(scanResult))
            {
                distinctNetworks.put(scanResult.SSID, scanResult); 
            }
            else
            {
                if(WifiManager.compareSignalLevel(scanResult.level, distinctNetworks.get(scanResult.SSID).level)>0)
                {
                    distinctNetworks.put(scanResult.SSID, scanResult);
                }
            }
        }
    }
    Set<String> networks  = distinctNetworks.keySet();// This will only contain one key which will be ths ssid with the max strength containing "open" in SSID
    for (String s : networks) {
        return s;
    }
}

- Sahil Bahl