有没有人有一个深度克隆 WPF 对象并保留数据绑定的好例子?
标记答案是第一部分。
第二部分是你必须创建一个 ExpressionConverter 并将其注入到序列化过程中。详情请参见:
http://www.codeproject.com/KB/WPF/xamlwriterandbinding.aspx?fid=1428301&df=90&mpp=25&noise=3&sort=Position&view=Quick&select=2801571
有没有人有一个深度克隆 WPF 对象并保留数据绑定的好例子?
标记答案是第一部分。
第二部分是你必须创建一个 ExpressionConverter 并将其注入到序列化过程中。详情请参见:
http://www.codeproject.com/KB/WPF/xamlwriterandbinding.aspx?fid=1428301&df=90&mpp=25&noise=3&sort=Position&view=Quick&select=2801571
我最简单的做法是使用XamlWriter将WPF对象保存为字符串。Save方法将序列化对象及其逻辑树中所有子元素。现在,您可以创建一个新对象并使用XamlReader加载它。
例如:将对象写入xaml(假设该对象是Grid控件):
string gridXaml = XamlWriter.Save(myGrid);
将其加载到一个新对象中:
StringReader stringReader = new StringReader(gridXaml);
XmlReader xmlReader = XmlReader.Create(stringReader);
Grid newGrid = (Grid)XamlReader.Load(xmlReader);
var sb = new StringBuilder();
var writer = XmlWriter.Create(sb, new XmlWriterSettings
{
Indent = true,
ConformanceLevel = ConformanceLevel.Fragment,
OmitXmlDeclaration = true,
NamespaceHandling = NamespaceHandling.OmitDuplicates,
});
var mgr = new XamlDesignerSerializationManager(writer);
// HERE BE MAGIC!!!
mgr.XamlWriterMode = XamlWriterMode.Expression;
// THERE WERE MAGIC!!!
System.Windows.Markup.XamlWriter.Save(this, mgr);
return sb.ToString();
/// <summary>
/// Extension methods for the WPF Binding class.
/// </summary>
public static class BindingExtensions
{
public static BindingBase CloneViaXamlSerialization(this BindingBase binding)
{
var sb = new StringBuilder();
var writer = XmlWriter.Create(sb, new XmlWriterSettings
{
Indent = true,
ConformanceLevel = ConformanceLevel.Fragment,
OmitXmlDeclaration = true,
NamespaceHandling = NamespaceHandling.OmitDuplicates,
});
var mgr = new XamlDesignerSerializationManager(writer);
// HERE BE MAGIC!!!
mgr.XamlWriterMode = XamlWriterMode.Expression;
// THERE WERE MAGIC!!!
System.Windows.Markup.XamlWriter.Save(binding, mgr);
StringReader stringReader = new StringReader(sb.ToString());
XmlReader xmlReader = XmlReader.Create(stringReader);
object newBinding = (object)XamlReader.Load(xmlReader);
if (newBinding == null)
{
throw new ArgumentNullException("Binding could not be cloned via Xaml Serialization Stack.");
}
if (newBinding is Binding)
{
return (Binding)newBinding;
}
else if (newBinding is MultiBinding)
{
return (MultiBinding)newBinding;
}
else if (newBinding is PriorityBinding)
{
return (PriorityBinding)newBinding;
}
else
{
throw new InvalidOperationException("Binding could not be cast.");
}
}
}
这样怎么样:
public static T DeepClone<T>(T from)
{
using (MemoryStream s = new MemoryStream())
{
BinaryFormatter f = new BinaryFormatter();
f.Serialize(s, from);
s.Position = 0;
object clone = f.Deserialize(s);
return (T)clone;
}
}
当然,这个深度克隆任何对象,并不一定是最快的解决方案,但它需要的维护最少... :)