ListView中的复选框无法正常工作

3

我正在为每个listview项目实现带有复选框的列表视图。我的问题是,当我单击任何一个复选框并滚动时,一些其他未被单击的复选框也会随机被单击。我查看了许多SO链接,但没有解决我的问题。

public class CustomListViewAdapter extends ArrayAdapter<Client> {

ViewHolder holder = null;
private LayoutInflater inflator = null;
private ArrayList<Client> orderList = null;
ArrayList<View> allViews;

public CustomListViewAdapter(Context context, int resource,
        List<Client> objects) {
    super(context, resource, objects);

    orderList = (ArrayList<Client>) objects;
    inflator = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    allViews = new ArrayList<View>();
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    if(convertView == null) {
        convertView = inflator.inflate(R.layout.listview_add_order, null);
        holder = new ViewHolder();
        convertView.setTag(holder);
        holder.txtViewName = (TextView) convertView.findViewById(R.id.txtViewAddOrder);
        holder.spinnerAddorder = (Spinner) convertView.findViewById(R.id.spinnerAddOrder);
        holder.checkAddorder = (CheckBox) convertView.findViewById(R.id.checkAddOrder);
        holder.checkAddorder.setTag(holder);
    } else {
        holder = (ViewHolder) convertView.getTag();


        holder.checkAddorder.setTag(holder);
    }

    allViews.add(position, holder.spinnerAddorder);

    holder.checkAddorder.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View view) {
            CheckBox cchk = (CheckBox)view;
            ViewHolder checkPosition = (ViewHolder) view.getTag();


            if(cchk.isChecked()) {

                checkPosition.spinnerAddorder.setVisibility(View.VISIBLE);

            } else {
                checkPosition.spinnerAddorder.setVisibility(View.INVISIBLE);
            }
        }
    });

    List<String> list = new ArrayList<String>();
    list.add("Select Quantity");
    list.add("1");
    list.add("2");
    list.add("3");
    ArrayAdapter<String> dataAdapter = new ArrayAdapter<String>(this.getContext(),R.layout.spinner_add_order_style, list);
    dataAdapter.setDropDownViewResource(android.R.layout.simple_spinner_item);
    holder.spinnerAddorder.setAdapter(dataAdapter);

    if(holder.checkAddorder.isChecked()) {


        ViewHolder checkPosition = (ViewHolder) holder.checkAddorder.getTag();
        checkPosition.spinnerAddorder.setVisibility(View.VISIBLE);
    } else {

        ViewHolder checkPosition = (ViewHolder) holder.checkAddorder.getTag();
        checkPosition.spinnerAddorder.setVisibility(View.INVISIBLE);
    }


    Client order = orderList.get(position);

    holder.txtViewName.setText(order.getFirstName());
    return  convertView;
}

private static class ViewHolder {
    public TextView txtViewName = null;
    public Spinner spinnerAddorder = null;
    public CheckBox checkAddorder = null;
}

     }

我的 XML 文件是

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:gravity="center_vertical"
android:orientation="horizontal"
android:paddingLeft="5dp"
android:paddingRight="5dp"
android:weightSum="2" >

<TextView
    android:id="@+id/txtViewAddOrder"
    android:layout_width="0dp"
    android:layout_height="match_parent"
    android:layout_weight="1.2"
    android:text="TextView"
    android:textSize="25sp" />

<Spinner
    android:id="@+id/spinnerAddOrder"
    android:layout_width="0dp"
    android:layout_height="wrap_content"
    android:layout_weight=".8"
    android:background="@drawable/dropdown" />

<CheckBox
    android:id="@+id/checkAddOrder"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_marginLeft="20dp" />

 </LinearLayout>

你能给我展示一下这个适配器类的 XML 文件吗? - ckpatel
@ChiragPatel 这个问题会发生是因为listview回收它的视图。Koded101发布的内容完全正确,不需要xml文件。 - Pragnani
@chirag 我添加了 XML 文件。 - Avinash
4个回答

5
这是由于视图回收所导致的。您需要做的是维护一个布尔数组,每次选中复选框时切换相应的布尔值。然后在您的getview中检查相应的布尔数组位置并设置复选框的状态。
类似这样:我已经修改了它以正确显示。未检查您的其余代码进展。 ^_^
public class CustomListViewAdapter extends ArrayAdapter<Client> {

ViewHolder holder = null;
private LayoutInflater inflator = null;
private ArrayList<Client> orderList = null;
ArrayList<View> allViews;

boolean[] checkedStates; //********** NEW ********

public CustomListViewAdapter(Context context, int resource,
        List<Client> objects) {
    super(context, resource, objects);

    orderList = (ArrayList<Client>) objects;
    inflator = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    allViews = new ArrayList<View>();

    checkedStates = new boolean[objects.size()]; //********** NEW ********
}

@Override   //********** NEW ******** position argument is now final 
public View getView(final int position, View convertView, ViewGroup parent) {
    if(convertView == null) {
        convertView = inflator.inflate(R.layout.listview_add_order, null);
        holder = new ViewHolder();
        convertView.setTag(holder);
        holder.txtViewName = (TextView) convertView.findViewById(R.id.txtViewAddOrder);
        holder.spinnerAddorder = (Spinner) convertView.findViewById(R.id.spinnerAddOrder);
        holder.checkAddorder = (CheckBox) convertView.findViewById(R.id.checkAddOrder);
        holder.checkAddorder.setTag(holder);
    } else {
        holder = (ViewHolder) convertView.getTag();


        holder.checkAddorder.setTag(holder);
    }

    allViews.add(position, holder.spinnerAddorder);

    holder.checkAddorder.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View view) {

              checkedStates[position] = !checkedStates[position]; //********** NEW ********
        }
    });

    holder.chechAddorder.setChecked(checkedStates[position]); //********** NEW ********

    List<String> list = new ArrayList<String>();
    list.add("Select Quantity");
    list.add("1");
    list.add("2");
    list.add("3");
    ArrayAdapter<String> dataAdapter = new ArrayAdapter<String>(this.getContext(),R.layout.spinner_add_order_style, list);
    dataAdapter.setDropDownViewResource(android.R.layout.simple_spinner_item);
    holder.spinnerAddorder.setAdapter(dataAdapter);

    if(checkedStates[position]) { //********** NEWEST ******** assuming true is checked and false is unchecked


        ViewHolder checkPosition = (ViewHolder) holder.checkAddorder.getTag();
        checkPosition.spinnerAddorder.setVisibility(View.VISIBLE);
    } else {

        ViewHolder checkPosition = (ViewHolder) holder.checkAddorder.getTag();
        checkPosition.spinnerAddorder.setVisibility(View.INVISIBLE);
    }


    Client order = orderList.get(position);

    holder.txtViewName.setText(order.getFirstName());
    return  convertView;
}

private static class ViewHolder {
    public TextView txtViewName = null;
    public Spinner spinnerAddorder = null;
    public CheckBox checkAddorder = null;
}

     }

你发布的内容完全正确,但请给他提供一些代码片段。 - Pragnani
是的,它运行得很好,但在滚动列表视图后更新了选中或未选中状态。 - Avinash
它仍然在做同样的事情? - Koded101
它完美地工作了。它检查或取消选中正确的项目,但只有在滚动列表视图后才显示或隐藏相应的旋转器。 - Avinash Kumar Pankaj
现在已经更新了,你需要更改isChecked行以显示/隐藏。如果可以工作,请告诉我! - Koded101

1

只需将focusable属性设置为false。 在适配器中为CheckBox设置onClickListener。

{ <CheckBox
    android:id="@+id/cb_alert"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_alignParentRight="true"
    android:layout_centerVertical="true"
    android:layout_marginRight="5dip"
    android:button="@drawable/custom_checkbox"
    android:checked="true"
    android:focusable="false"
    android:padding="7dip" />}

0
使用双向数据绑定来处理复选框状态 https://developer.android.com/topic/libraries/data-binding/two-way#kotlin

<CheckBox
android:id="@+id/rememberMeCheckBox"
android:checked="@={viewmodel.rememberMe}"

/>

登录视图模型类:BaseObservable { // val data = ...

@Bindable
fun getRememberMe(): Boolean {
    return data.rememberMe
}

fun setRememberMe(value: Boolean) {
    // Avoids infinite loops.
    if (data.rememberMe != value) {
        data.rememberMe = value

        // React to the change.
        saveData()

        // Notify observers of a new value.
        notifyPropertyChanged(BR.remember_me)
    }
}

}


1
欢迎提供解决方案的链接,但请确保您的答案即使没有链接也是有用的:在链接周围添加上下文,以便其他用户了解它的内容和原因,然后引用您链接的页面中最相关的部分,以防目标页面不可用。仅仅提供链接的答案可能会被删除。 - Das_Geek

0

在您的适配器中覆盖这些方法:

override fun getItemId(position: Int) = position.toLong()

override fun getItemViewType(position: Int) = position

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