Pug（前身为Jade）中的多行变量

Question

这个可以使用吗？例如在这里：

- var movieList = [{title: "Ocean's Eleven", rating: 9.2}, {title: "Pirates of the Caribbean", rating: 9.7}];

mixin movie-card(movie)
  h2.movie-title= movie.title
  div.rating
    p= movie.rating

for movie in movieList
  +movie-card(movie)

我不想在每一行开头使用-。如果不可能，也许有一种方法可以导入多行JSON文件吗？

- Entry Guy

---

很遗憾，除非有人提出拉取请求（pull request），否则这个功能不会被实现：https://github.com/pugjs/pug/issues/796 - YakovL

Answer 1

自2.0.3版本起，可以使用以下语法：

-
  var arr = ["Very", "Long",
             "Array"];

拉取请求链接：https://github.com/pugjs/pug/pull/1965

- user2988142

Answer 2

在编译期间，您可以使用LOCALS（Jade）或DATA（Pug）导入JSON数据。这是我通过gulpjs和Pug执行的方式，movieList将是在gulpfile.js中创建的数据，songs.json将是一个外部文件。从您的代码示例中不清楚您是使用任务管理器还是express等...

gulpfile.js

var fs = require('fs'),
    gulp = require('gulp'),
    pug = require('gulp-pug'),
    movieList = [{title: "Ocean's Eleven", rating: 9.2}, {title: "Pirates of the Caribbean", rating: 9.7}];

gulp.task('markup', function() {
  gulp.src('./markup/*.pug')
    .pipe(pug({
      data: {
      // in Jade, this would be "locals: {"
        "movies": movieList,
        "music": JSON.parse( fs.readFileSync('./songs.json', { encoding: 'utf8' }) )
      }
    )
    .pipe(gulp.dest('../'))
  });
});

在Pug模板中

- var movieList = locals['movies'] // assuming this will eventually be "= data['movies']"
- var musicList = locals['music'] // assuming this will eventually be "= data['music']"

mixin movie-card(movie)
  h2.movie-title= movie.title
  div.rating
    p= movie.rating

for movie in movieList
  +movie-card(movie)

mixin song-card(song)
  h2.song-title #{song.title}
  div.rating
    p #{song.rating}

for song in musicList
  +song-card(song)

- Jason Lydon