我已经编写了一个Java测试。它将一条消息放入队列并将其作为字符串返回。我的目标是将其转换为Java对象SignUpDto。我已经尽可能地精简了问题的代码。
问题是:如何修改下面的测试以将其转换为对象?
SignUpClass
应用程序 - 配置类
问题是:如何修改下面的测试以将其转换为对象?
SignUpClass
public class SignUpDto {
private String customerName;
private String isoCountryCode;
... etc
}
应用程序 - 配置类
@Configuration
public class Application {
@Bean
public ConnectionFactory connectionFactory() {
return new CachingConnectionFactory("localhost");
}
@Bean
public AmqpAdmin amqpAdmin() {
return new RabbitAdmin(connectionFactory());
}
@Bean
public RabbitTemplate rabbitTemplate() {
// updated with @GaryRussels feedback
RabbitTemplate rabbitTemplate = new RabbitTemplate(connectionFactory());
rabbitTemplate.setMessageConverter(new Jackson2JsonMessageConverter());
return rabbitTemplate;
}
@Bean
public Queue myQueue() {
return new Queue("myqueue");
}
}
考试
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(classes = {Application.class})
public class TestQueue {
@Test
public void convertMessageIntoObject(){
ApplicationContext context = new AnnotationConfigApplicationContext(Application.class);
AmqpTemplate template = context.getBean(AmqpTemplate.class);
String jsonString = "{ \"customerName\": \"TestName\", \"isoCountryCode\": \"UK\" }";
template.convertAndSend("myqueue", jsonString);
String foo = (String) template.receiveAndConvert("myqueue");
// this works ok
System.out.println(foo);
// How do I make this convert
//SignUpDto objFoo = (SignUpDto) template.receiveAndConvert("myqueue");
// objFoo.toString()
}
}
RabbitTemplate
@Bean
定义中:template.setMessageConverter(new Jackson2JsonMessageConverter());
。 - Gary Russell