是否可以有多个抽象接口的部分实现,然后通过使用多重继承将这些部分实现收集到一个具体类中?
我有以下示例代码:
#include <iostream>
struct Base
{
virtual void F1() = 0;
virtual void F2() = 0;
};
struct D1 : Base
{
void F1() override { std::cout << __func__ << std::endl; }
};
struct D2 : Base
{
void F2() override { std::cout << __func__ << std::endl; }
};
// collection of the two partial implementations to form the concrete implementation
struct Deriv : D1, D2
{
using D1::F1; // I added these using clauses when it first didn't compile - they don't help
using D2::F2;
};
int main()
{
Deriv d;
return 0;
}
以下是编译错误信息:
main.cpp: In function ‘int main()’:
main.cpp:27:11: error: cannot declare variable ‘d’ to be of abstract type ‘Deriv’
main.cpp:19:8: note: because the following virtual functions are pure within ‘Deriv’:
main.cpp:5:18: note: virtual void Base::F1()
main.cpp:6:18: note: virtual void Base::F2()
struct D1 : Base
” 这里为什么要使用公有继承?D1
对客户端代码有用处吗? - curiousguy