我正在尝试使用d3.js创建半圆形,就像这个。 我没有找到如何实现的例子。 如何使用d3.js实现?
是的,您可以使用SVG渐变来实现。您需要定义它,并将其用作圆形的填充即可。
var grad = svg.append("defs").append("linearGradient").attr("id", "grad")
.attr("x1", "0%").attr("x2", "0%").attr("y1", "100%").attr("y2", "0%");
grad.append("stop").attr("offset", "50%").style("stop-color", "lightblue");
grad.append("stop").attr("offset", "50%").style("stop-color", "white");
svg.append("circle")
.attr("fill", "url(#grad)");
这里是JSfiddle 链接。
<svg height="200"> <a transform="translate(100,100)">
<g>
<circle fill="#f60" r="50"></circle>
</g>
<g>
<clippath id="g-clip">
<rect height="50" id="g-clip-rect" width="100" x="-50" y="-50">
</rect>
</clippath>
<circle clip-path="url(#g-clip)" fill="#fff" r="47"></circle>
</g>
</a>
</svg>
我已经创建了一个jsfiddle示例,以说明这一点:http://jsfiddle.net/neqeT/2/
<div id="id_circle"></div>
<script>
var svg = d3.select("#id_circle")
.append("svg")
.attr("width",250)
.attr("height",250);
var grad = svg.append("defs")
.append("linearGradient").attr("id", "grad")
.attr("x1", "0%").attr("x2", "0%").attr("y1", "100%").attr("y2", "0%");
grad.append("stop").attr("offset", "50%").style("stop-color", "lightblue");
grad.append("stop").attr("offset", "50%").style("stop-color", "white");
svg.append("circle")
.attr("r",50)
.attr("cx",60)
.attr("cy",60)
.style("stroke","black")
.style("fill","url(#grad)");
</script>