如何使用联系人ID获取特定的联系电话号码

Question

这里显示我的联系人名称列表。通过单击列表，我可以得到ContactName和Contact Id。从中，我想要通过使用Contact ID或Contact name来获取电话号码，请帮助我。

以下是我的代码

void ReadContacts(String sort) {
    final Uri uri = ContactsContract.Contacts.CONTENT_URI;
    final String[] projection = new String[] {
            ContactsContract.Contacts._ID,
            ContactsContract.Contacts.DISPLAY_NAME
    };
    //boolean mShowInvisible = false;
    String selection = ContactsContract.Contacts.IN_VISIBLE_GROUP + " = '1'";
    String[] selectionArgs = null;
    final String sortOrder = ContactsContract.Contacts.DISPLAY_NAME + " COLLATE LOCALIZED ASC";

    m_curContacts = managedQuery(uri, projection, selection, selectionArgs, sortOrder);
    String[] fields = new String[] {ContactsContract.Data.DISPLAY_NAME};
    m_slvAdapter = new SimpleCursorAdapter(this, 
                android.R.layout.simple_list_item_1, 
                m_curContacts,
                fields, 
                new int[] {android.R.id.text1});
    m_slvAdapter.setFilterQueryProvider(new FilterQueryProvider() {

        public Cursor runQuery(CharSequence constraint) {
            Log.d(LOG_TAG, "runQuery constraint:"+constraint);
            String selection = ContactsContract.Contacts.IN_VISIBLE_GROUP + " = '1'" +
                    " AND "+ ContactsContract.Contacts.DISPLAY_NAME + " LIKE '%"+constraint+"%'";
            String[] selectionArgs = null;//new String[]{"'1'"};//, };
            Cursor cur = managedQuery(uri, projection, selection, selectionArgs, sortOrder);
            return cur;
        }

   });
   m_lvContacts.setAdapter(m_slvAdapter); 
   //  cur.close();

}



public void onItemClick(AdapterView<?> arg0, View v, int position, long id) {
    ContentResolver cr;
    Cursor cursor = (Cursor) m_lvContacts.getItemAtPosition(position);
    String szDisplayName = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts.DISPLAY_NAME));
    String szId = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
    int nId = cursor.getInt(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
    Log.d(LOG_TAG, "Item click:"+position+" szId:"+szId+" nId:"+nId+" Data:"+szDisplayName);
    Toast.makeText(getBaseContext(), "Item click:"+phoneNumber+" szId:"+szId+" nId:"+nId+" Data:"+szDisplayName, Toast.LENGTH_SHORT).show();

}

- user933909

---

请查看此处：https://dev59.com/-k_Ta4cB1Zd3GeqPAm-6 - Shahzad Imam

我使用了上面的链接，但是phoneindex没有产生任何值。 - user933909

请尝试在SO上搜索。类似的问题已经被问过了，你只需要整理一下即可。该问题涉及从Android联系人选择器中获取联系人信息。 - Shahzad Imam

Answer 1

试试这个

ArrayList<String> phones = new ArrayList<String>();

Cursor cursor = mContentResolver.query(
        CommonDataKinds.Phone.CONTENT_URI, 
        null, 
        CommonDataKinds.Phone.CONTACT_ID +" = ?", 
        new String[]{id}, null);

while (cursor.moveToNext()) 
{
    phones.add(cursor.getString(cursor.getColumnIndex(CommonDataKinds.Phone.NUMBER)));
} 

cursor.close();
return(phones);

- Dhaval

---

我不需要电话号码列表，我需要一个特定的号码。 - user933909

你检查了吗？我认为它只返回一个数字。 - Dhaval

Answer 2

试试这个

public void getNameUsingContactId(String contactId){

    String cContactIdString = ContactsContract.Contacts._ID;
    Uri cCONTACT_CONTENT_URI = ContactsContract.Contacts.CONTENT_URI;
    String cDisplayNameColumn = ContactsContract.Contacts.DISPLAY_NAME;

    String selection = cContactIdString + " = ? ";
    String[] selectionArgs = new String[]{String.valueOf(contactId)};

    Cursor cursor = mContext.getContentResolver().query(cCONTACT_CONTENT_URI, null, selection, selectionArgs, null);
    if ((cursor != null) && (cursor.getCount() > 0)) {
        cursor.moveToFirst();
        while ((cursor != null) && (cursor.isAfterLast() == false)) {
            if (cursor.getColumnIndex(cContactIdString) >= 0) {
                if (contactId.equals(cursor.getString(cursor.getColumnIndex(cContactIdString)))) {
                    String name = cursor.getString(cursor.getColumnIndex(cDisplayNameColumn));
                     break;
                }
            }
            cursor.moveToNext();
        }
    }
    if (cursor != null)
        cursor.close();  
}   

- Siddarth Kanted

Answer 3

大家好，我找到了答案：

如果需要，请使用以下代码：

  Cursor cursor = (Cursor) m_lvContacts.getItemAtPosition(position);
        String szDisplayName = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts.DISPLAY_NAME));
        String szId = cursor.getString(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
        int nId = cursor.getInt(cursor.getColumnIndexOrThrow( ContactsContract.Contacts._ID));
         long l = Long.parseLong(szId);
        int type=ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE;




 cursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
         null,
         ContactsContract.CommonDataKinds.Phone.CONTACT_ID+"='"+szId+"'",
         null, null);

            int phoneNumberIndex = cursor
                    .getColumnIndexOrThrow(ContactsContract.CommonDataKinds.Phone.NUMBER);

            Log.d(TAG, String.valueOf(cursor.getCount()));

            if (cursor != null) {
                Log.v(TAG, "Cursor Not null");
                try {
                    if (cursor.moveToNext()) {
                        Log.v(TAG, "Moved to first");
                        Log.v(TAG, "Cursor Moved to first and checking");
                        phoneNumber = cursor.getString(phoneNumberIndex);
                        System.out.println("HAGSd"+phoneNumber);
                    }
                } finally {
                    Log.v(TAG, "In finally");
                    cursor.close();
                }

- user933909

Answer 4

public static final String contactIdByPhoneNumber(Context ctx, String phoneNumber) {
    String contactId = null;
    if (phoneNumber != null && phoneNumber.length() > 0) {
        ContentResolver contentResolver = ctx.getContentResolver();

        Uri uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(phoneNumber));

        String[] projection = new String[] { PhoneLookup._ID };

        Cursor cursor = contentResolver.query(uri, projection, null, null, null);

        if (cursor != null) {
            while (cursor.moveToNext()) {
                contactId = cursor.getString(cursor.getColumnIndexOrThrow(PhoneLookup._ID));
            }
            cursor.close();
        }
    }
    return contactId;
}

- Hardip

Answer 5

您可以在数据表中找到电话号码。在rawcontacts表中查找相应的原始联系人ID（使用联系人ID作为where条件），使用这些原始联系人ID查询数据表。电话号码将具有特定的MIME类型（现在远离文档），因此您可以识别它们。 希望这可以帮助您！

提示：从模拟器/设备中复制contacts2.db数据库，并使用Squirrel（SQLite jdbc驱动程序）在联系人数据库中进行探索。该数据库位于/data/data/下，查找列表中的联系人。

- Sveinung Kval Bakken