OneSignal发布通知Android

Question

我需要在我的安卓应用中使用postNotification。以下是我目前的代码，但它无法正常工作：

try {
    OneSignal.postNotification(new JSONObject("{'contents': {'en':'Test Message'}, 'include_player_ids': ['" + userId + "']}"), null);
} catch (JSONException e) {
     e.printStackTrace();
}

- user3656460

Answer 1

请确保userId中的值是您账户上有效的OneSignal ID，并且已订阅。

您也可以使用以下代码添加logcat日志以调试该问题。

try {
  OneSignal.postNotification(new JSONObject("{'contents': {'en':'Test Message'}, 'include_player_ids': ['" + "userId" + "']}"),
     new OneSignal.PostNotificationResponseHandler() {
       @Override
       public void onSuccess(JSONObject response) {
         Log.i("OneSignalExample", "postNotification Success: " + response.toString());
       }
       @Override
       public void onFailure(JSONObject response) {
         Log.e("OneSignalExample", "postNotification Failure: " + response.toString());
       }
     });
} catch (JSONException e) {
  e.printStackTrace();
}

- jkasten

Answer 2

这对我有用，检查是否创建了id，然后发布通知

OneSignal.idsAvailable(new OneSignal.IdsAvailableHandler() {
            @Override
            public void idsAvailable(String userId, String registrationId) {
                Log.d("debug", "UserId:" + userId);
                if (registrationId != null) {
                    String msg_welcome  = getResources().getString(R.string.msg_welcome);
                    Log.d("debug", "registrationId:" + registrationId);
                    try {
                        OneSignal.postNotification(new JSONObject("{'contents': {'en': '"+ msg_welcome +"'}, 'include_player_ids': ['" + userId + "']}"),
                                new OneSignal.PostNotificationResponseHandler() {
                                    @Override
                                    public void onSuccess(JSONObject response) {
                                        Log.i("OneSignalExample", "postNotification Success: " + response.toString());

                                    }

                                    @Override
                                    public void onFailure(JSONObject response) {
                                        Log.e("OneSignalExample", "postNotification Failure: " + response.toString());
                                    }
                                });
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                }
            }
        });

- Naveen Dew