Spring Data JPA如何传递日期参数

4

我正在一个使用Spring MVC和Spring Data的项目中工作,我想要向本地查询传递一个日期参数,目前我已经有了以下代码。

这是我的查询方法,它在一个继承自JpaRepository的接口中:

 @Query(value  = 
            "SELECT "
                + "a.name, a.lastname
            + "FROM "
                + "person  a, "
                + "myTable b "
            + "WHERE "
            + "a.name= ?1' "
            + "AND a.birthday = ?2 ",
         nativeQuery = true)
    public ArrayList<Object> personInfo(String name, String dateBirthDay);

实现此接口定义的方法为:
public ArrayList<Object> getPersonsList(String name, String dateBirthDay) {

            ArrayList<Object> results= null;

            results= serviceAutowiredVariable.personInfo(name, dateBirthDay);

            return results;
        }

这是我从控制器类中调用它的方式。

personsList= _serviceAutowiredVariable.getPersonsList("Jack", "TO_DATE('01-08-2013', 'DD-MM-YYYY')" );

我猜想在这行代码中:"AND a.birthday = ?2 "?2等于这个字符串:TO_DATE('01-08-2013', 'DD-MM-YYYY')

但是当我运行代码时,出现了以下错误:

    [Request processing failed; nested exception is org.springframework.orm.jpa.JpaSystemException: org.hibernate.exception.DataException: could not extract ResultSet; nested exception is javax.persistence.PersistenceException: org.hibernate.exception.DataException: could not extract ResultSet] root cause
java.sql.SQLDataException: ORA-01858: a non-numeric character was found where a numeric was expected

ERROR: org.hibernate.engine.jdbc.spi.SqlExceptionHelper - ORA-01858: a non-numeric character was found where a numeric was expected

1
只需传递一个 Date 对象而不是一个 String - M. Deinum
1个回答

14

你可以使用这样的结构:

import org.springframework.data.repository.query.Param;
...

@Query(value  = 
    " SELECT a.id, a.lastname FROM person a" + 
    " WHERE a.name = :name AND a.birthday = :date ", nativeQuery = true)
public List<Object[]> getPersonInfo(
    @Param("name") String name, 
    @Param("date") Date date);

我犯了一个打字错误——getPersonInfo需要两个参数:当然是String类型和Date类型。我刚刚编辑过来修复了这个问题。 - przemek hertel

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