$("#startDate, #endDate").datetimepicker({ dateFormat: 'yyyy-mm-dd hh:mm:ss'});
检查yyyy-mm-dd hh:mm:ss字符串是否相互比较非常容易，因为它们已经按顺序排列;您可以忘记数字的基数，并像字符串比较一样简单地执行<或>。这可能不适用于其他日期。
function compISOZDate(d1, d2) { // d1 is
if (d1 < d2) return -1; // smaller
if (d1 === d2) return 0; // the same
/* else */ return 1; // bigger
}
验证日期有些复杂，因为月份的天数可能会变化。您可以忽略此事实并仅测试数字，但我更喜欢半途而废，引入上限。
function verifyMyDate(d) {
var re = /^\d{4}-(0[1-9]|1[0-2])-([0-2]\d|3[01]) (0\d|1[01]):[0-5]\d:[0-5]\d$/;
// yyyy - MM - dd hh : mm : ss
return re.test(d);
}
var d1 = '2013-10-07 11:58:26',
d2 = '2012-06-14 19:22:03';
// check
if (!verifyMyDate(d1)) throw new Error('Invalid date: ' + d1);
if (!verifyMyDate(d2)) throw new Error('Invalid date: ' + d2);
// compare
compISOZDate(d1, d2); // 1, d1 is bigger than d2
// also
compISOZDate(d2, d1); // -1
compISOZDate(d1, d1); // 0
Date对象。因此，您可以执行类似以下的操作。
Javascript
var iso8601 = "2013-02-01 10:00:00",
userDate = new Date(iso8601),
today = new Date(),
dateTime,
date,
time,
value;
// check is valid date
if (isNaN(userDate)) {
alert("invalid userDate");
}
// check if userDate is before today
if (userDate.getDate() < today.getDate()) {
alert("userDate is in past");
}
// check the string specifically matches "yyyy-mm-dd hh:mm:ss" and is valid
function isGregorianLeapYear(year) {
return year % 400 === 0 || year % 100 !== 0 && year % 4 === 0;
}
function daysInGregorianMonth(year, month) {
var days;
if (month == 2) {
days = 28;
if (isGregorianLeapYear(year)) {
days += 1;
}
} else {
days = 31 - ((month - 1) % 7 % 2);
}
return days;
}
if (typeof iso8601 !== "string") {
alert("not an iso8601 string");
} else {
dateTime = iso8601.split(" ");
if (dateTime.length !== 2) {
alert("missing date or time element");
} else {
date = dateTime[0].split("-");
if (date.length !== 3) {
alert("incorrect number of date elements");
} else {
value = +date[0];
if (date[0].length !== 4 || value < -9999 || value > 9999) {
alert("year value is incorrect");
}
value = +date[1];
if (date[1].length !== 2 || value < 1 || value > 12) {
alert("month value is incorrect");
}
value = +date[2];
if (date[2].length !== 2 || value < 1 || value > daysInGregorianMonth(+date[0], +date[1])) {
alert("day value is incorrect");
}
}
time = dateTime[1].split(":");
if (time.length !== 3) {
alert("incorrect number of time elements");
} else {
value = +time[0];
if (time[0].length !== 2 || value < 0 || value > 23) {
alert("hour value is incorrect");
}
value = +time[1];
if (time[1].length !== 2 || value < 0 || value > 59) {
alert("minute value is incorrect");
}
value = +time[2];
if (time[2].length !== 2 || value < 0 || value > 59) {
alert("second value is incorrect");
}
}
}
}
console.log(userDate);
console.log(today);
将ValidateDate函数内的RegExp更改为以下代码
function ValidateDate(dtValue)
{
var dtRegex = new RegExp(/\b\d{4}[\/-]\d{1,2}[\/-]\b\d{1,2} (0\d|1[01]):[0-5]\d:[0-5]\d$\b/);
return dtRegex.test(dtValue);
}
尝试这个并让我知道，同样的方法你也可以验证hh:mm:ss
对于24小时制，使用而不是AM/PM：
regex = new RegExp(^\d{4}-(0[1-9]|1[0-2])-([0-2]\d|3[01]) (0\d|1\d|2[0-3]):[0-5]\d:[0-5]\d$);
这是我写的代码，运行良好：
function validateDate(dtValue) {
// Format expected dd/mm/aaaa or dd-mm-aaaa (French Date)
// Accept also d/m/aaaa or d-m-aaaa (ok for MySQL Database to have one number only for days and months)
// Before the insert into database I will convert to aaaa-mm-jj or aaaa-m-j
var dtRegex = new RegExp(/\b(0?[1-9]|([1-2]?[0-9]|3[0-1]))[\/-]([0]?[1-9]|1[0-2])[\/-]\b\d{4} ([0-1]?[0-9]|2[0-3]):[0-5]\d$\b/);
// Accept range => (01 to 31) (/ or -) (01 to 12) (/ or -) (4 numbers) space (00 to 23) : (00 to 59)
var bValidateDate= dtRegex.test(dtValue);
// Test if bValidateDate true, test and throw out (accepted from regex expression) :
// 30/02, 31/02, 31/04, 31/06, 31/09, 31/11
// 30-02, 31-02, 31-04, 31-06, 31-09, 31-11
// Get the 5 first characters
var sFebruary29= dtValue.substring(0, 5);
if (bValidateDate)
{
var aOfDateErrors= ["30/02", "31/02", "31/04", "31/06", "31/09", "31/11", "30-02", "31-02", "31-04", "31-06", "31-09", "31-11"];
if (aOfDateErrors.indexOf(sFebruary29) > -1)
{
bValidateDate= false;
}
}
// Then, if bValidateDate is still true (good format)
// check if the date is a leap year to accept 29/02 or 29-02
// And finally, my customer asked me to have a year between 2017 and now
if (bValidateDate)
{
// Get the year
var sYear= dtValue.substring(6, 10);
// Customer's constraints
var bYearCustomerOK= ((parseInt(sYear) >= 2017) && (parseInt(sYear) <= new Date().getFullYear()));
// I promise, this is the "last test'em all !"
var bFinalDate= (bYearCustomerOK) && (sYear % 400 === 0 || sYear % 100 !== 0 && sYear % 4 === 0) && ((sFebruary29 == "29/02") ||(sFebruary29 == "29-02"));
if (! bFinalDate)
{
bValidateDate= false;
}
}
return bValidateDate;
}
请您知道如果发现了错误的日期，请告诉我：）
alert。 - Paul S.