private Mat drawLargestContour(Mat input) {
/** Allocates and returns a black matrix with the
* largest contour of the input matrix drawn in white. */
List<MatOfPoint> contours = new ArrayList<MatOfPoint>();
Imgproc.findContours(input, contours, new Mat() /* hierarchy */,
Imgproc.RETR_EXTERNAL, Imgproc.CHAIN_APPROX_SIMPLE);
double maxArea = 0;
int index = -1;
for (MatOfPoint contour : contours) { // iterate over every contour in the list
double area = Imgproc.contourArea(contour);
if (area > maxArea) {
maxArea = area;
index = contours.indexOf(contour);
}
}
if (index == -1) {
Log.e(TAG, "Fatal error: no contours in the image!");
}
Mat border = new Mat(input.rows(), input.cols(), CvType.CV_8UC1); // initialized to 0 (black) by default because it's Java :)
Imgproc.drawContours(border, contours, index, new Scalar(255)); // 255 = draw contours in white
return border;
}
您可以尝试两件事情:
阈值化后,您可以:
进行形态学闭运算,
或者,最简单的方法是:使用cv::findContours
,保留最大的轮廓(如果有多个),然后使用cv::fillConvexPoly
绘制它,您将得到这个掩码。(fillConvexPoly
会为您填充孔洞)