我收到了一个错误:java.net.MalformedURLException: Protocol not found
我想读取网络上的一个HTML文件。
mainfest ::::: uses-permission android:name="android.permission.INTERNET"
uses-permission android:name="android.permission.ACCESS_NETWORK_STATE"
import com.doviz.R.id;
import android.os.Bundle;
import android.app.Activity;
import android.view.Menu;
import android.widget.TextView;
import android.widget.Toast;
public class MainActivity extends Activity {
public String inputLine;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
String myUri = "";
myUri = "www.tcmb.gov.tr/kurlar/today.html";
Toast.makeText( this, "step-1 " , Toast.LENGTH_LONG).show();
try{
Toast.makeText( this, "step -2" , Toast.LENGTH_LONG).show();
myUri = "www.tcmb.gov.tr/kurlar/today.html";
URL url = new URL(myUri);
Toast.makeText( this, "step-3" , Toast.LENGTH_LONG).show();
final InputStream is =url.openStream();
Toast.makeText( this, "step -4" , Toast.LENGTH_LONG).show();
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
Toast.makeText( this, "step -5 " , Toast.LENGTH_LONG).show();
String line;
Toast.makeText( this, "step-6" , Toast.LENGTH_LONG).show();
while ((line=reader.readLine())!=null){
// page.add(line);
}
Toast.makeText( this, " step-7" , Toast.LENGTH_LONG).show();
}
catch(Exception e){
//e.printStackTrace();
TextView tx =(TextView)findViewById(id.TextView1);
tx.setText(myUri + " >>> "+ e.getMessage());
Toast.makeText( this, "problem = " + e.getMessage() + " -- "+ e.getLocalizedMessage(), Toast.LENGTH_LONG).show();
//System.exit(1);
}
Toast.makeText( this, "step -8" , Toast.LENGTH_LONG).show();
}