我正在实现一个应用程序,它将重复我所说的一切。
我需要做的就是将我录制的声音播放到缓冲区中,只有一秒的延迟,
这样我会听到自己说话,但是会有1秒的延迟。
这是Recorder类的run方法:
public void run()
{
AudioRecord recorder = null;
int ix = 0;
buffers = new byte[256][160];
try
{
int N = AudioRecord.getMinBufferSize(44100,AudioFormat.CHANNEL_IN_STEREO,AudioFormat.ENCODING_PCM_16BIT);
recorder = new AudioRecord(AudioSource.MIC, 44100, AudioFormat.CHANNEL_IN_STEREO, AudioFormat.ENCODING_PCM_16BIT, N*10);
recorder.startRecording();
Timer t = new Timer();
SeekBar barra = (SeekBar)findViewById(R.id.barraDelay);
t.schedule(r = new Reproductor(), barra.getProgress());
while(!stopped)
{
byte[] buffer = buffers[ix++ % buffers.length];
N = recorder.read(buffer,0,buffer.length);
}
}
catch(Throwable x)
{
}
finally
{
recorder.stop();
recorder.release();
recorder = null;
}
这是我的播放器的第一次运行:
public void run() {
reproducir = true;
AudioTrack track = null;
int jx = 0;
try
{
int N = AudioRecord.getMinBufferSize(44100,AudioFormat.CHANNEL_IN_STEREO,AudioFormat.ENCODING_PCM_16BIT);
track = new AudioTrack(AudioManager.STREAM_MUSIC, 44100,
AudioFormat.CHANNEL_OUT_STEREO, AudioFormat.ENCODING_PCM_16BIT, N*10, AudioTrack.MODE_STREAM);
track.play();
/*
* Loops until something outside of this thread stops it.
* Reads the data from the recorder and writes it to the audio track for playback.
*/
while(reproducir)
{
byte[] buffer = buffers[jx++ % buffers.length];
track.write(buffer, 0, buffer.length);
}
}
catch(Throwable x)
{
}
/*
* Frees the thread's resources after the loop completes so that it can be run again
*/
finally
{
track.stop();
track.release();
track = null;
}
}
Reproductor是一个内部类,扩展了TimerTask并实现了"run"方法。
非常感谢!