如何使用JavaScript在Script Editor Web Part中获取当前用户的名称?
如何使用JavaScript在Script Editor Web Part中获取当前用户的名称?
这是对我有效的代码:
<script src="/SiteAssets/jquery.SPServices-2013.02a.js" type="text/javascript"></script>
<script src="/SiteAssets/jquery.js" type="text/javascript"></script>
<script type="text/javascript">
var userid= _spPageContextInfo.userId;
var requestUri = _spPageContextInfo.webAbsoluteUrl + "/_api/web/getuserbyid(" + userid + ")";
var requestHeaders = { "accept" : "application/json;odata=verbose" };
$.ajax({
url : requestUri,
contentType : "application/json;odata=verbose",
headers : requestHeaders,
success : onSuccess,
error : onError
});
function onSuccess(data, request){
var loginName = data.d.Title;
alert(loginName);
}
function onError(error) {
alert("error");
}
</script>
我发现了一种更简单的方法,它甚至不需要使用SP.UserProfiles.js。我不知道它是否适用于每个人的特定情况,但绝对值得分享。
//assume we have a client context called context.
var web = context.get_web();
var user = web.get_currentUser(); //must load this to access info.
context.load(user);
context.executeQueryAsync(function(){
alert("User is: " + user.get_title()); //there is also id, email, so this is pretty useful.
}, function(){alert(":(");});
无论如何,感谢你的回答,我通过与UserProfiles打交道了解到了一些东西,尽管这对我的情况并不是必需的。
如果您在SharePoint页面中,只需使用以下代码:
_spPageContextInfo.userId;
这个怎么样:
$.getJSON(_spPageContextInfo.webServerRelativeUrl + "/_api/web/currentuser")
.done(function(data){
console.log(data.Title);
})
.fail(function() { console.log("Failed")});
jQuery.ajax({
url: _spPageContextInfo.webServerRelativeUrl + "/_api/web/currentuser",
type: "GET",
headers: { "Accept": "application/json;odata=verbose" }
}).done(function( data ){
console.log( data );
console.log( data.d.Title );
}).fail(function(){
console.log( failed );
});
gotAccount
中以获取想要的格式的名称。<script type="text/javascript" src="/_layouts/15/SP.js"></script>
<script type="text/javascript" src="/_layouts/15/SP.UserProfiles.js"></script>
<script type="text/javascript">
var personProperties;
SP.SOD.executeOrDelayUntilScriptLoaded(getCurrentUser, 'SP.UserProfiles.js');
function getCurrentUser() {
var clientContext = new SP.ClientContext.get_current();
personProperties = new SP.UserProfiles.PeopleManager(clientContext).getMyProperties();
clientContext.load(personProperties);
clientContext.executeQueryAsync(gotAccount, requestFailed);
}
function gotAccount(sender, args) {
alert("Display Name: "+ personProperties.get_displayName() +
", Account Name: " + personProperties.get_accountName());
}
function requestFailed(sender, args) {
alert('Cannot get user account information: ' + args.get_message());
}
</script>
personProperties.get_userProfileProperties()
获得一个包含所有属性的完整对象,包括不能通过getter函数获取的自定义属性。 - Martin BraunU can use javascript to achive that like this:
function loadConstants() {
this.clientContext = new SP.ClientContext.get_current();
this.clientContext = new SP.ClientContext.get_current();
this.oWeb = clientContext.get_web();
currentUser = this.oWeb.get_currentUser();
this.clientContext.load(currentUser);
completefunc:this.clientContext.executeQueryAsync(Function.createDelegate(this,this.onQuerySucceeded), Function.createDelegate(this,this.onQueryFailed));
}
//U must set a timeout to recivie the exactly user u want:
function onQuerySucceeded(sender, args) {
window.setTimeout("ttt();",1000);
}
function onQueryFailed(sender, args) {
console.log(args.get_message());
}
//By using a proper timeout, u can get current user :
function ttt(){
var clientContext = new SP.ClientContext.get_current();
var groupCollection = clientContext.get_web().get_siteGroups();
visitorsGroup = groupCollection.getByName('OLAP Portal Members');
t=this.currentUser .get_loginName().toLowerCase();
console.log ('this.currentUser .get_loginName() : '+ t);
}
我必须使用XML来完成它,将以下内容放入内容编辑器Web部件中,方法是添加一个内容编辑器Web部件,编辑该Web部件,然后单击“编辑源”按钮并粘贴以下内容:
<input type="button" onclick="GetUserInfo()" value="Show Domain, Username and Email"/>
<script type="text/javascript">
function GetUserInfo() {
$.ajax({
type: "GET",
url: "https://<ENTER YOUR DOMAIN HERE>/_api/web/currentuser",
dataType: "xml",
error: function (e) {
alert("An error occurred while processing XML file" + e.toString());
console.log("XML reading Failed: ", e);
},
success: function (response) {
var content = $(response).find("content");
var spsEmail = content.find("d\\:Email").text();
var rawLoginName = content.find("d\\:LoginName").text();
var spsDomainUser = rawLoginName.slice(rawLoginName.indexOf('|') + 1);
var indexOfSlash = spsDomainUser.indexOf('\\') + 1;
var spsDomain = spsDomainUser.slice(0, indexOfSlash - 1);
var spsUser = spsDomainUser.slice(indexOfSlash);
alert("Domain: " + spsDomain + " User: " + spsUser + " Email: " + spsEmail);
}
});
}
</script>
请点击以下链接查看您的数据是XML还是JSON格式:
在被接受的答案中,Kate使用了这种方法:
var userid= _spPageContextInfo.userId;
var requestUri = _spPageContextInfo.webAbsoluteUrl + "/_api/web/getuserbyid(" + userid + ")
如果您知道用户的ID,可以使用以下函数:
function getUser(id){
var returnValue;
jQuery.ajax({
url: "http://YourSite/_api/Web/GetUserById(" + id + ")",
type: "GET",
headers: { "Accept": "application/json;odata=verbose" },
success: function(data) {
var dataResults = data.d;
alert(dataResults.Title);
}
});
}
或者你可以尝试
var listURL = _spPageContextInfo.webAbsoluteUrl + "/_api/web/currentuser";
您可以使用SP页面上下文信息:
_spPageContextOnfo.userLoginName
_spPageContextInfo.webAbsoluteUrl
是不起作用的。在这里可以查看更多信息。 - mohsenof_spPageContextInfo.userDisplayName
或_spPageContextInfo.userEmail
来获取用户名或电子邮件地址。 - jdgregson