我希望通过编写一个非常简单的内核来学习。在阅读了大量关于PIC和x86架构中IRQ的文章后,我发现IRQ1
是键盘处理程序。我正在使用以下代码打印所按下的键:
#include "port_io.h"
#define IDT_SIZE 256
#define PIC_1_CTRL 0x20
#define PIC_2_CTRL 0xA0
#define PIC_1_DATA 0x21
#define PIC_2_DATA 0xA1
void keyboard_handler();
void load_idt(void*);
struct idt_entry
{
unsigned short int offset_lowerbits;
unsigned short int selector;
unsigned char zero;
unsigned char flags;
unsigned short int offset_higherbits;
};
struct idt_pointer
{
unsigned short limit;
unsigned int base;
};
struct idt_entry idt_table[IDT_SIZE];
struct idt_pointer idt_ptr;
void load_idt_entry(char isr_number, unsigned long base, short int selector, char flags)
{
idt_table[isr_number].offset_lowerbits = base & 0xFFFF;
idt_table[isr_number].offset_higherbits = (base >> 16) & 0xFFFF;
idt_table[isr_number].selector = selector;
idt_table[isr_number].flags = flags;
idt_table[isr_number].zero = 0;
}
static void initialize_idt_pointer()
{
idt_ptr.limit = (sizeof(struct idt_entry) * IDT_SIZE) - 1;
idt_ptr.base = (unsigned int)&idt_table;
}
static void initialize_pic()
{
/* ICW1 - begin initialization */
write_port(PIC_1_CTRL, 0x11);
write_port(PIC_2_CTRL, 0x11);
/* ICW2 - remap offset address of idt_table */
/*
* In x86 protected mode, we have to remap the PICs beyond 0x20 because
* Intel have designated the first 32 interrupts as "reserved" for cpu exceptions
*/
write_port(PIC_1_DATA, 0x20);
write_port(PIC_2_DATA, 0x28);
/* ICW3 - setup cascading */
write_port(PIC_1_DATA, 0x00);
write_port(PIC_2_DATA, 0x00);
/* ICW4 - environment info */
write_port(PIC_1_DATA, 0x01);
write_port(PIC_2_DATA, 0x01);
/* Initialization finished */
/* mask interrupts */
write_port(0x21 , 0xff);
write_port(0xA1 , 0xff);
}
void idt_init()
{
initialize_pic();
initialize_idt_pointer();
load_idt(&idt_ptr);
}
load_idt
只是使用了x86指令lidt
。之后我加载了键盘处理程序:
void kmain(void)
{
//Using grub bootloader..
idt_init();
kb_init();
load_idt_entry(0x21, (unsigned long) keyboard_handler, 0x08, 0x8e);
}
这是实现代码:
#include "kprintf.h"
#include "port_io.h"
#include "keyboard_map.h"
void kb_init(void)
{
/* 0xFD is 11111101 - enables only IRQ1 (keyboard)*/
write_port(0x21 , 0xFD);
}
void keyboard_handler(void)
{
unsigned char status;
char keycode;
char *vidptr = (char*)0xb8000; //video mem begins here.
/* Acknownlegment */
int current_loc = 0;
status = read_port(0x64);
/* Lowest bit of status will be set if buffer is not empty */
if (status & 0x01) {
keycode = read_port(0x60);
if(keycode < 0)
return;
vidptr[current_loc++] = keyboard_map[keycode];
vidptr[current_loc++] = 0x07;
}
write_port(0x20, 0x20);
}
这是我使用的额外代码:
section .text
global load_idt
global keyboard_handler
extern kprintf
extern keyboard_handler_main
load_idt:
sti
mov edx, [esp + 4]
lidt [edx]
ret
global read_port
global write_port
; arg: int, port number.
read_port:
mov edx, [esp + 4]
in al, dx
ret
; arg: int, (dx)port number
; int, (al)value to write
write_port:
mov edx, [esp + 4]
mov al, [esp + 4 + 4]
out dx, al
ret
这是我的入口点:
bits 32
section .text
;grub bootloader header
align 4
dd 0x1BADB002 ;magic
dd 0x00 ;flags
dd - (0x1BADB002 + 0x00) ;checksum. m+f+c should be zero
global start
extern kmain
start:
; cli ;block interrupts
mov esp, stack_space ;set stack pointer
call kmain
hlt ;halt the CPU
section .bss
resb 8192 ;8KB for stack
stack_space:
我正在使用QEMU运行内核:
qemu-system-i386 -kernel kernel
问题是屏幕上没有显示任何字符。相反,我仍然得到相同的输出:
SeaBIOS (version Ubuntu-1.8.2-1-ubuntu1)
Booting from ROM...
我该如何解决这个问题?有什么建议吗?
keyboard_handler
是否被执行过?read_port(0x64)
是否表示缓冲区为空?从端口0x60
读取的值是否为负数? - Tsyvarev