在新的API更改下,您如何在Keras中进行层间逐元素乘法? 在旧的API下,我会尝试像这样:
merge([dense_all, dense_att], output_shape=10, mode='mul')
我尝试了这个(MWE):
from keras.models import Model
from keras.layers import Input, Dense, Multiply
def sample_model():
model_in = Input(shape=(10,))
dense_all = Dense(10,)(model_in)
dense_att = Dense(10, activation='softmax')(model_in)
att_mull = Multiply([dense_all, dense_att]) #merge([dense_all, dense_att], output_shape=10, mode='mul')
model_out = Dense(10, activation="sigmoid")(att_mull)
return 0
if __name__ == '__main__':
sample_model()
完整的跟踪信息:
Using TensorFlow backend.
Traceback (most recent call last):
File "testJan17.py", line 13, in <module>
sample_model()
File "testJan17.py", line 8, in sample_model
att_mull = Multiply([dense_all, dense_att]) #merge([dense_all, dense_att], output_shape=10, mode='mul')
TypeError: __init__() takes exactly 1 argument (2 given)
编辑:
我尝试实现tensorflow的逐元素乘法函数。当然,结果不是Layer()
实例,所以它不能工作。以下是为了纪念而尝试的代码:
def new_multiply(inputs): #assume two only - bad practice, but for illustration...
return tf.multiply(inputs[0], inputs[1])
def sample_model():
model_in = Input(shape=(10,))
dense_all = Dense(10,)(model_in)
dense_att = Dense(10, activation='softmax')(model_in) #which interactions are important?
new_mult = new_multiply([dense_all, dense_att])
model_out = Dense(10, activation="sigmoid")(new_mult)
model = Model(inputs=model_in, outputs=model_out)
model.compile(optimizer='adam', loss='categorical_crossentropy', metrics=['accuracy'])
return model
multiply()
是Multiply()
的包装器。 - Alexey Romanov