我在我的工作MSBuild项目中有以下定义...
<MSBuild
Projects="$(MSBuildProjectFile)"
Condition="'@(FilesToCompile)' != ''"
Targets="buildcpp"
Properties="CPPFILE=%(FilesToCompile.FullPath);OBJFILE=$(ObjectFolder)\%(FilesToCompile.Filename).doj;IncludeDirs=$(IncludeDirs)"
/>
...接着是目标的定义。
注意目标的定义中包含对另一个目标compilecpp
的调用...
<Target Name="buildcpp">
<PropertyGroup>
<CompileDefines Condition="'$(PreprocessorDefinitions)' != ''">-D$(PreprocessorDefinitions.Replace(";"," -D"))</CompileDefines>
</PropertyGroup>
<Exec
EchoOff="true"
StandardOutputImportance="low"
StandardErrorImportance="low"
IgnoreExitCode="true"
ConsoleToMSBuild="true"
Command='
"$(CompilerExe)" ^
$(HWProcessor) ^
$(IncludeDirs) ^
$(CompilerOptions) ^
$(CompileDefines) ^
"$(CPPFILE)" ^
-MM
'>
<Output TaskParameter="ConsoleOutput" PropertyName="output_cppdeps"/>
<Output TaskParameter="ExitCode" PropertyName="exitcode_cppdeps"/>
</Exec>
<MSBuild
Projects="$(MSBuildProjectFile)"
Condition="'$(exitcode_cppdeps)' == '0'"
Targets="compilecpp"
Properties="INPUTFILES=$(BuildCppDeps)"
/>
</Target>
......尽管调用者从未传入,但它使用属性$(OBJFILE)
<Target Name="compilecpp" Inputs="$(INPUTFILES)" Outputs="$(OBJFILE)">
<Message Importance="high" Text="$(CPPFILE): Compiling..."/>
...
问题
既然这个msbuild可以工作,那么我可以推断出$(OBJFILE)
是可访问的;为什么它是可访问的?属性的范围规则是什么?