使用Py4j从Python向Java传递可变参数

6

我正在尝试从Python向Java代码传递可变参数。

Java代码: LogDebugCmd.java

public class LogDebugCmd implements Command {
  private Class clazz;
  private String format;
  private Object[] args;

  public LogDebugCmd() {}
  public void setLog(String format, Object... args) {
    this.format = format;
    this.args = args.clone();
    clazz = getClass();
  }

  @Override
  public void execute() {
    VLog.getLog(clazz).debug(format, args);
  }

CommandEntryPoint.java

public class CommandEntryPoint {
  private LogDebugCmd logDebugCmd;

  public CommandEntryPoint() {
    logDebugCmd = new LogDebugCmd();

  public LogDebugCmd getLogDebugCmd(String str, Object... args) {
    setLog(str, args);
    return logDebugCmd;
  }
  public static void main(String args[]) {
    GatewayServer gatewayServer = new GatewayServer(new CommandEntryPoint());
    gatewayServer.start();
    System.out.println("Gateway Server Started");
  }

Python 代码 test.py:

from py4j.java_gateway import JavaGateway
gateway = JavaGateway()
logDebugCmd = gateway.entry_point.getLogDebugCmd("Step 01 - Test initiated.")
logDebugCmd..execute()

错误:

Traceback (most recent call last):
  File "C:/Python27/Lib/site-packages/py4j-0.10.3-py2.7.egg/py4j/sampleTLStest.py", line 4, in <module>
    logDebugCmd = gateway.entry_point.getLogDebugCmd("Step 01 - Test initiated.")
  File "C:\Python27\lib\site-packages\py4j-0.10.3-py2.7.egg\py4j\java_gateway.py", line 1133, in __call__
    answer, self.gateway_client, self.target_id, self.name)
  File "C:\Python27\lib\site-packages\py4j-0.10.3-py2.7.egg\py4j\protocol.py", line 323, in get_return_value
    format(target_id, ".", name, value))
***Py4JError: An error occurred while calling t.getLogDebugCmd. 
Trace:
py4j.Py4JException: Method getLogDebugCmd([class java.lang.String]) does not exist at py4j.reflection.ReflectionEngine.getMethod(ReflectionEngine.java:318)
at py4j.reflection.ReflectionEngine.getMethod(ReflectionEngine.java:326)
at py4j.Gateway.invoke(Gateway.java:272)
at py4j.commands.AbstractCommand.invokeMethod(AbstractCommand.java:132)
at py4j.commands.CallCommand.execute(CallCommand.java:79)
at py4j.GatewayConnection.run(GatewayConnection.java:214)
at java.lang.Thread.run(Thread.java:745)***

有没有一种方式可以将可变参数传递给Java?我正在尝试将String作为第二个参数传递给getLogDebugCmd(),但也出现错误。
1个回答

6

可变参数实际上被表示为数组,因此您可以这样做:

# Pass a None if you have no varargs
logDebugCmd = gateway.entry_point.getLogDebugCmd("Step 01 - Test initiated.", None)

# Create an array of objects
object_class = gateway.jvm.Object
object_array = gateway.new_array(object_class, 2)
object_array[0] = "foo"
object_array[1] = "bar"
logDebugCmd = gateway.entry_point.getLogDebugCmd("Step 01 - Test initiated.", object_array)

有一个拉取请求来改善Py4J中的可变参数支持,但它存在一些编译问题,因此尚未合并。


谢谢您的快速回复,@Barthelemy!这很有帮助。 - Pooja
只需要一个更正,就是在传递“None”之前将其转换为“Object”类型,以便在Object数组的位置上传递Null对象而不是null。后者会导致NullPointerException。参考:链接。例如: object_array [0] = None logDebugCmd = gateway.entry_point.getLogDebugCmd(“Step 01 - Test initiated。”,object_array) - Pooja
实际上,这取决于被调用的代码:如果它检查args是否为空,那么你就不会得到NullPointerException。现在想想看,最好创建一个空数组:object_array = gateway.new_array(object_class, 0)。 - Barthelemy

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