在标签内将光标更改为指针

Question

我正在网站上使用纯CSS样式来设置单选按钮（从这里获取），但是我无法将光标更改为指针，包括标签和标签内的span（这是样式化单选按钮本身的内容）。 标记

<div class="demonstration pureCSS">
  <div>
    <input id="checkboxPureCSS1" type="checkbox" name="checkboxPureCSS" value="1" checked="checked"><label for="checkboxPureCSS1"><span></span>Option 1</label>
  </div>
  <div>
    <input id="checkboxPureCSS2" type="checkbox" name="checkboxPureCSS" value="2"><label for="checkboxPureCSS2"><span></span>Option 2</label>
  </div>
  <div>
    <input id="checkboxPureCSS3" type="checkbox" name="checkboxPureCSS" value="3"><label for="checkboxPureCSS3"><span></span>Option 3</label>
  </div>
</div>

<br />

<div class="demonstration pureCSS">
  <div>
    <input id="radioPureCSS1" type="radio" name="radioPureCSS" value="1" checked="checked"><label for="radioPureCSS1"><span><span></span></span>Option 1</label>
  </div>
  <div>
    <input id="radioPureCSS2" type="radio" name="radioPureCSS" value="2"><label for="radioPureCSS2"><span><span></span></span>Option 2</label>
  </div>
  <div>
    <input id="radioPureCSS3" type="radio" name="radioPureCSS" value="3"><label for="radioPureCSS3"><span><span></span></span>Option 3</label>
  </div>
</div>

CSS

.pureCSS input[type=checkbox]:not(old),
.pureCSS input[type=radio   ]:not(old){
  width     : 2em;
  margin    : 0;
  padding   : 0;
  font-size : 1em;
  opacity   : 0;
}

.pureCSS input[type=checkbox]:not(old) + label,
.pureCSS input[type=radio   ]:not(old) + label{
  display      : inline-block;
  margin-left  : -2em;
  line-height  : 1.5em;
  cursor: pointer;
}

.pureCSS input[type=checkbox]:not(old) + label > span,
.pureCSS input[type=radio   ]:not(old) + label > span{
  display          : inline-block;
  width            : 0.875em;
  height           : 0.875em;
  margin           : 0.25em 0.5em 0.25em 0.25em;
  border           : 0.0625em solid rgb(192,192,192);
  border-radius    : 0.25em;
  background       : rgb(224,224,224);
  background-image :    -moz-linear-gradient(rgb(240,240,240),rgb(224,224,224));
  background-image :     -ms-linear-gradient(rgb(240,240,240),rgb(224,224,224));
  background-image :      -o-linear-gradient(rgb(240,240,240),rgb(224,224,224));
  background-image : -webkit-linear-gradient(rgb(240,240,240),rgb(224,224,224));
  background-image :         linear-gradient(rgb(240,240,240),rgb(224,224,224));
  vertical-align   : bottom;
}

.pureCSS input[type=checkbox]:not(old):checked + label > span,
.pureCSS input[type=radio   ]:not(old):checked + label > span{
  background-image :    -moz-linear-gradient(rgb(224,224,224),rgb(240,240,240));
  background-image :     -ms-linear-gradient(rgb(224,224,224),rgb(240,240,240));
  background-image :      -o-linear-gradient(rgb(224,224,224),rgb(240,240,240));
  background-image : -webkit-linear-gradient(rgb(224,224,224),rgb(240,240,240));
  background-image :         linear-gradient(rgb(224,224,224),rgb(240,240,240));
}

.pureCSS input[type=checkbox]:not(old):checked + label > span:before{
  content     : '✓';
  display     : block;
  width       : 1em;
  color       : rgb(153,204,102);
  font-size   : 0.875em;
  line-height : 1em;
  text-align  : center;
  text-shadow : 0 0 0.0714em rgb(115,153,77);
  font-weight : bold;
}

.pureCSS input[type=radio]:not(old):checked +  label > span > span{
  display          : block;
  width            : 0.5em;
  height           : 0.5em;
  margin           : 0.125em;
  border           : 0.0625em solid rgb(115,153,77);
  border-radius    : 0.125em;
  background       : rgb(153,204,102);
  background-image :    -moz-linear-gradient(rgb(179,217,140),rgb(153,204,102));
  background-image :     -ms-linear-gradient(rgb(179,217,140),rgb(153,204,102));
  background-image :      -o-linear-gradient(rgb(179,217,140),rgb(153,204,102));
  background-image : -webkit-linear-gradient(rgb(179,217,140),rgb(153,204,102));
  background-image :         linear-gradient(rgb(179,217,140),rgb(153,204,102));
}

我已经复制了一个场景，链接为jsfiddle，并将光标设置为标签的指针，但是当您将光标悬停在单选按钮上时，光标返回到默认状态。是否可能在单选按钮悬停时更改光标为指针？我尝试在上设置cursor: pointer，但似乎没有任何效果。

- zigojacko

Answer 1

只需添加希望，就可能奏效。

input[type=radio]:hover{
  cursor: pointer;
}

- Rahul Kashyap

Answer 2

添加 cursor: pointer;

.pureCSS input[type="checkbox"]:not(old), .pureCSS input[type="radio"]:not(old) {
    cursor: pointer;
    font-size: 1em;
    margin: 0;
    opacity: 0;
    padding: 0;
    width: 2em;
}

https://jsfiddle.net/csrr3axq/2/

- Lalji Tadhani

---

谢谢。我试图将它添加到错误的样式中。现在运行得很好！ :) - zigojacko