使用数组键创建新数组

Question

鉴于：

$data = array(
    "some"  => "163",
    "rand"  => "630",
    "om"    => "43",
    "words" => "924",
    "as"    => "4",
    "keys"  => "54"
);

我希望创建一个新数组，只包含与某些特定键匹配的键：

$keys = array( "some", "thing", "rand", "keys" );

我想返回一个包含这些共同键的数组，创建如下：

$arr = array(
     "some"   => "163",
     "rand"   => "630",
     "keys"   => "54"
);

- Alex V

Answer 1

你可以使用 array_intersect_key() 和 array_flip() 实现此功能：

$arr = array_intersect_key($data, array_flip($keys));

结果：

数组
(
    [some] => 163
    [rand] => 630
    [keys] => 54
)

该结果为一个数组，包含三个键值对，分别是“some”、“rand”和“keys”，对应的值分别为163、630和54。

- user142162

Answer 2

$filteredArray = array_intersect_key($data, array_flip($keys)); 

这是最简单的解决方案，

但为了与众不同：

$data = array(
    "some"  => "163",
    "rand"  => "630",
    "om"    => "43",
    "words" => "924",
    "as"    => "4",
    "keys"  => "54"
);

$keys = array( "some", "thing", "rand", "keys" );

$filteredArray = array_filter($data,function($item) use (&$data,$keys) { $retVal = false; if (in_array(key($data),$keys)) $retVal = true; next($data); return $retVal; });

var_dump($filteredArray);

- Mark Baker

Answer 3

$result = array_intersect_key($data, array_flip($keys));

- goat