在VB.NET中将十六进制数（而不是ASCII十六进制值）转换为字符串

Question

我已经尝试搜索此内容，但大多数人只想将十六进制值转换为其ASCII等效项。这不是我要做的。

我想知道VB.NET是否有一个简单的内置函数可以做到这一点：

    Private Function NibbleToString(ByVal Nibble As Byte) As String
    Dim retval As String = String.Empty
    Select Case Nibble

        Case &H0
            retval = "0"
        Case &H1
            retval = "1"
        Case &H2
            retval = "2"
        Case &H3
            retval = "3"
        Case &H4
            retval = "4"
        Case &H5
            retval = "5"
        Case &H6
            retval = "6"
        Case &H7
            retval = "7"
        Case &H8
            retval = "8"
        Case &H9
            retval = "9"
        Case &HA
            retval = "A"
        Case &HB
            retval = "B"
        Case &HC
            retval = "C"
        Case &HD
            retval = "D"
        Case &HE
            retval = "E"
        Case &HF
            retval = "F"
    End Select

    Return retval
End Function

有没有更优雅的方法来完成与该代码相同的事情？

- avword

Answer 1

使用具有X格式说明符的ToString方法：

Dim b As Byte = &HA3
Console.WriteLine(b.ToString("X"))    ' displays "A3"

Dim i As Integer = &H12AB89EF
Console.WriteLine(i.ToString("X"))    ' displays "12AB89EF"

如果您出于某种原因只想一次处理部分数据，那么您可以在处理数字之前屏蔽/移位各个比特位：

Dim b As Byte = &H5E
Console.WriteLine((b And &HF).ToString("X"))    ' displays "E" (low nibble)
Console.WriteLine((b >> 4).ToString("X"))       ' displays "5" (high nibble)

- LukeH

Answer 2

作为一个函数

<FlagsAttribute()> _
Public Enum whichNibble As Integer
    'byte
    '7654 3210
    ' msn  lsn
    lsn = 1
    msn = 2
    both = lsn Or msn
End Enum

Private Function GetNibble(ByVal aByte As Byte, _
                          Optional ByVal whNib As whichNibble = whichNibble.lsn) As String
    Select Case whNib
        Case whichNibble.both
            Return aByte.ToString("X2")
        Case whichNibble.lsn
            Return (aByte And &HF).ToString("X")
        Case whichNibble.msn
            Return ((aByte >> 4) And &HF).ToString("X")
    End Select
End Function

- dbasnett