Java Swing鼠标拖放绘制矩形

5

我正在创建一个矩形绘图程序。只有在程序拖到底部时才会绘制正方形。即使向其他方向拖动,我也希望确保正方形被正确绘制。我该如何解决这个问题?

**DrawRect.java**


    import javax.swing.*;

    import java.awt.*;

    import java.awt.event.*;

    public class DrawRect extends JPanel {

        int x, y, w, h;
        public static void main(String [] args) { 
            JFrame f = new JFrame("Draw Box Mouse 2");
            f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); 
            f.setContentPane(new DrawRect());
            f.setSize(300, 300); f.setVisible(true);
        }



        DrawRect() { 
            x = y = w = h = 0; // 
            MyMouseListener listener = new MyMouseListener(); 
            addMouseListener(listener); 
            addMouseMotionListener(listener);    
        }

        public void setStartPoint(int x, int y) {
            this.x = x; this.y = y;
        }

        public void setEndPoint(int x, int y) { 
            w = Math.abs(this.x - x); 
            h = Math.abs(this.y - y); 
        }

        class MyMouseListener extends MouseAdapter {
            public void mousePressed(MouseEvent e) {
                setStartPoint(e.getX(), e.getY());
            } 
            public void mouseDragged(MouseEvent e) { 
                setEndPoint(e.getX(), e.getY()); repaint(); 
            } 
            public void mouseReleased(MouseEvent e) {
                setEndPoint(e.getX(), e.getY()); repaint(); 
            } 
        }

        public void paintComponent(Graphics g) {
            super.paintComponent(g);
            g.setColor(Color.RED); 

Please help me.
            g.drawRect(x, y, w, h); 

        }



    }
1个回答

9

试试这个。

你需要仔细确定起点。起点是第一个和最后一个鼠标坐标的最小x和y点。

以下是解决此问题的步骤:

  1. 当鼠标点击时,获取第一个坐标x,y
  2. 当鼠标拖动时,获取最后一个坐标x2,y2
  3. 将最小的x和y坐标作为drawRect的起点 Math.min(x,x2);
  4. 使用坐标差的绝对值来计算矩形的高度和宽度。 Math.abs(x-x2);

代码

import javax.swing.*;

import java.awt.*;

import java.awt.event.*;

    public class DrawRect extends JPanel {

        int x, y, x2, y2;

        public static void main(String[] args) {
            JFrame f = new JFrame("Draw Box Mouse 2");
            f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
            f.setContentPane(new DrawRect());
            f.setSize(300, 300);
            f.setVisible(true);
        }

        DrawRect() {
            x = y = x2 = y2 = 0; // 
            MyMouseListener listener = new MyMouseListener();
            addMouseListener(listener);
            addMouseMotionListener(listener);
        }

        public void setStartPoint(int x, int y) {
            this.x = x;
            this.y = y;
        }

        public void setEndPoint(int x, int y) {
            x2 = (x);
            y2 = (y);
        }

        public void drawPerfectRect(Graphics g, int x, int y, int x2, int y2) {
            int px = Math.min(x,x2);
            int py = Math.min(y,y2);
            int pw=Math.abs(x-x2);
            int ph=Math.abs(y-y2);
            g.drawRect(px, py, pw, ph);
        }

        class MyMouseListener extends MouseAdapter {

            public void mousePressed(MouseEvent e) {
                setStartPoint(e.getX(), e.getY());
            }

            public void mouseDragged(MouseEvent e) {
                setEndPoint(e.getX(), e.getY());
                repaint();
            }

            public void mouseReleased(MouseEvent e) {
                setEndPoint(e.getX(), e.getY());
                repaint();
            }
        }

        public void paintComponent(Graphics g) {
            super.paintComponent(g);
            g.setColor(Color.RED);
            drawPerfectRect(g, x, y, x2, y2);
        }

    }

每次我们按下最后一个丢失的时候,我们不能取那个矩形吗? - Ahmad Sayeed

网页内容由stack overflow 提供, 点击上面的
可以查看英文原文,
原文链接