我有一个未排序的数组,如何最好地删除所有重复的元素?
例如:
a[1,5,2,6,8,9,1,1,10,3,2,4,1,3,11,3]
因此,在进行该操作后,数组应该看起来像
a[1,5,2,6,8,9,10,3,4,11]
我有一个未排序的数组,如何最好地删除所有重复的元素?
例如:
a[1,5,2,6,8,9,1,1,10,3,2,4,1,3,11,3]
因此,在进行该操作后,数组应该看起来像
a[1,5,2,6,8,9,10,3,4,11]
这是我用C++创建的代码段,试试看
#include <iostream>
using namespace std;
int main()
{
cout << " Delete the duplicate" << endl;
int numberOfLoop = 10;
int loopCount =0;
int indexOfLargeNumber = 0;
int largeValue = 0;
int indexOutput = 1;
//Array to hold the numbers
int arrayInt[10] = {};
int outputArray [10] = {};
// Loop for reading the numbers from the user input
while(loopCount < numberOfLoop){
cout << "Please enter one Integer number" << endl;
cin >> arrayInt[loopCount];
loopCount = loopCount + 1;
}
outputArray[0] = arrayInt[0];
int j;
for (int i = 1; i < numberOfLoop; i++) {
j = 0;
while ((outputArray[j] != arrayInt[i]) && j < indexOutput) {
j++;
}
if(j == indexOutput){
outputArray[indexOutput] = arrayInt[i];
indexOutput++;
}
}
cout << "Printing the Non duplicate array"<< endl;
//Reset the loop count
loopCount =0;
while(loopCount < numberOfLoop){
if(outputArray[loopCount] != 0){
cout << outputArray[loopCount] << endl;
}
loopCount = loopCount + 1;
}
return 0;
}
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collection;
import java.util.HashMap;
import java.util.HashSet;
import java.util.List;
import java.util.Set;
public class testing {
public static void main(String[] args) {
EligibleOffer efg = new EligibleOffer();
efg.setCode("1234");
efg.setName("hey");
EligibleOffer efg1 = new EligibleOffer();
efg1.setCode("1234");
efg1.setName("hey1");
EligibleOffer efg2 = new EligibleOffer();
efg2.setCode("1235");
efg2.setName("hey");
EligibleOffer efg3 = new EligibleOffer();
efg3.setCode("1235");
efg3.setName("hey");
EligibleOffer[] eligibleOffer = { efg, efg1,efg2 ,efg3};
removeDupliacte(eligibleOffer);
}
public static EligibleOffer[] removeDupliacte(EligibleOffer[] array) {
List list = Arrays.asList(array);
List list1 = new ArrayList();
int len = list.size();
for (int i = 0; i <= len-1; i++) {
boolean isDupliacte = false;
EligibleOffer eOfr = (EligibleOffer) list.get(i);
String value = eOfr.getCode().concat(eOfr.getName());
if (list1.isEmpty()) {
list1.add(list.get(i));
continue;
}
int len1 = list1.size();
for (int j = 0; j <= len1-1; j++) {
EligibleOffer eOfr1 = (EligibleOffer) list1.get(j);
String value1 = eOfr1.getCode().concat(eOfr1.getName());
if (value.equals(value1)) {
isDupliacte = true;
break;
}
System.out.println(value+"\t"+value1);
}
if (!isDupliacte) {
list1.add(eOfr);
}
}
System.out.println(list1);
EligibleOffer[] eligibleOffer = new EligibleOffer[list1.size()];
list1.toArray(eligibleOffer);
return eligibleOffer;
}
}
我的解决方案(O(N)
)不使用额外的内存,但是数组必须被排序(我的类使用插入排序算法,但这并不重要):
public class MyArray
{
//data arr
private int[] _arr;
//field length of my arr
private int _leght;
//counter of duplicate
private int countOfDup = 0;
//property length of my arr
public int Length
{
get
{
return _leght;
}
}
//constructor
public MyArray(int n)
{
_arr = new int[n];
_leght = 0;
}
// put element into array
public void Insert(int value)
{
_arr[_leght] = value;
_leght++;
}
//Display array
public void Display()
{
for (int i = 0; i < _leght; i++) Console.Out.Write(_arr[i] + " ");
}
//Insertion sort for sorting array
public void InsertSort()
{
int t, j;
for (int i = 1; i < _leght; i++)
{
t = _arr[i];
for (j = i; j > 0; )
{
if (_arr[j - 1] >= t)
{
_arr[j] = _arr[j - 1];
j--;
}
else break;
}
_arr[j] = t;
}
}
private void _markDuplicate()
{
//mark duplicate Int32.MinValue
for (int i = 0; i < _leght - 1; i++)
{
if (_arr[i] == _arr[i + 1])
{
countOfDup++;
_arr[i] = Int32.MinValue;
}
}
}
//remove duplicates O(N) ~ O(2N) ~ O(N + N)
public void RemoveDups()
{
_markDuplicate();
if (countOfDup == 0) return; //no duplicate
int temp = 0;
for (int i = 0; i < _leght; i++)
{
// if duplicate remember and continue
if (_arr[i] == Int32.MinValue) continue;
else //else need move
{
if (temp != i) _arr[temp] = _arr[i];
temp++;
}
}
_leght -= countOfDup;
}
}
和主要
static void Main(string[] args)
{
Random r = new Random(DateTime.Now.Millisecond);
int i = 11;
MyArray a = new MyArray(i);
for (int j = 0; j < i; j++)
{
a.Insert(r.Next(i - 1));
}
a.Display();
Console.Out.WriteLine();
a.InsertSort();
a.Display();
Console.Out.WriteLine();
a.RemoveDups();
a.Display();
Console.ReadKey();
}
[1, 2, 3, 2, 3, 1].uniq
- jtbandes