SQL Count where子句

Question

我有以下的SQL语句：

 SELECT        [l.LeagueId] AS LeagueId, [l.LeagueName] AS NAME, [lp.PositionId]
 FROM            (Leagues l INNER JOIN
                     Lineups lp ON l.LeagueId = lp.LeagueId)
 WHERE        (lp.PositionId = 1) OR
                     (lp.PositionId = 3) OR
                     (lp.PositionId = 2)

我需要的是获取行数大于某个数字的职位数量。类似于：

 SELECT        [l.LeagueId] AS LeagueId, [l.LeagueName] AS NAME, [lp.PositionId]
 FROM            (Leagues l INNER JOIN
                     Lineups lp ON l.LeagueId = lp.LeagueId)
 WHERE        Count(lp.PositionId = 1) > 2 OR
                     Count(lp.PositionId = 3) > 6 OR
                     Count(lp.PositionId = 2) > 3

有没有在SQL中实现这个的方法？

- Kris B

---

所以，我正在使用Cade Roux的解决方案，但是有没有人知道为什么当我将HAVING从OR语句更改为AND语句时，会得到零个结果？如果我只使用一个SUM（CASE..）语句，我会得到结果，但是如果我结合两个已经工作的语句，我会得到零个结果。 - Kris B

Answer 1

这个怎么样？

SELECT        [l.LeagueId] AS LeagueId, [l.LeagueName] AS NAME
 FROM            (Leagues l INNER JOIN
                     Lineups lp ON l.LeagueId = lp.LeagueId)
 GROUP BY [l.LeagueId], [l.LeagueName]
 HAVING        SUM(CASE WHEN lp.PositionId = 1 THEN 1 ELSE 0 END) > 2 OR
                     SUM(CASE WHEN lp.PositionId = 3 THEN 1 ELSE 0 END) > 6 OR
                     SUM(CASE WHEN lp.PositionId = 2 THEN 1 ELSE 0 END) > 3

- Cade Roux

Answer 2

你需要的关键词是HAVING：

HAVING是你要找的关键字：

SELECT        [l.LeagueId] AS LeagueId, [l.LeagueName] AS NAME, [lp.PositionId]
FROM            (Leagues l INNER JOIN
                     Lineups lp ON l.LeagueId = lp.LeagueId)
GROUP BY lp.PositionId, l.LeagueName
HAVING lp.PositionId = 1 AND COUNT(*) > 2 
       OR lp.PositionId = 2 AND COUNT(*) > 3 
       OR lp.PositionId = 3 AND COUNT(*) > 6 

- Scott Stafford