用户输入n个点。我需要检查多边形是否存在,然后确定其类型-凸多边形还是凹多边形。我知道如果多边形的每个角度都小于180度,则该多边形是凸多边形。因此,问题就是要找到多边形的每个内角。我一直在寻找公式或算法,但没有成功。
例子:
输入:n = 4;
点1: (5;6)
点2: (4;-5)
点3: (-5;4)
点4: (-5;5)
期望输出:多边形是凸多边形。
例子:
输入:n = 4;
点1: (5;6)
点2: (4;-5)
点3: (-5;4)
点4: (-5;5)
期望输出:多边形是凸多边形。
目前的代码如下:它只能找到平面上点之间的最大和最小距离。
#include "stdafx.h"
#include <iostream>
using namespace std;
int main()
{
double a[15][2];
int n;
cin >> n;
if (n <= 0 && n > 15)
return 1;
for (int i = 0; i < n; i++)
{
cout << "x" << i << " = , y" << i << " = ";
cin >> a[i][0] >> a[i][1];
}
double maxDistance = 0.0;
double minDistance = 0.0;
double maxpoint1[2];
double maxpoint2[2];
double minpoint1[2];
double minpoint2[2];
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
{
if (j != i)
{
double x1 = a[i][0];
double x2 = a[j][0];
double y1 = a[i][1];
double y2 = a[j][1];
double currentDistance = sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2));
if (currentDistance > maxDistance)
{
maxDistance = currentDistance;
maxpoint1[0] = x1;
maxpoint1[1] = y1;
maxpoint2[0] = x2;
maxpoint2[1] = y2;
}
if (minDistance > currentDistance)
{
currentDistance = minDistance;
minpoint1[0] = x1;
minpoint1[1] = y1;
minpoint2[0] = x2;
minpoint2[1] = y2;
}
cout << "x1 = " << x1 << " y1 = " << y1 << " x2 = " << x2 << " y2 = " << y2;
cout << endl << "Distance is " << currentDistance;
cout << endl;
}
}
}
cout << "The max distance is: " << maxDistance << " between x1 = " << maxpoint1[0] << " y1 = " << maxpoint1[1] << " and x2 = " << maxpoint2[0] << " y2 = " << maxpoint2[1];
cout << "The min distance is: " << minDistance << " between x1 = " << minpoint1[0] << " y1 = " << minpoint1[1] << " and x2 = " << minpoint2[0] << " y2 = " << minpoint2[1];
return 0;
}