基本上我需要一些帮助或建议来解决我的问题。我正在从数据库中填充我的列表视图,并且我需要在创建列表视图时检查position
上的项目ID是否与我的数据库中另一个表中的ID相同。如果是,您可以单击该项,如果不是,则禁用它,但是我找到的所有关于如何做到这一点的信息...我真的无法理解如何做到这一点。
import java.util.ArrayList;
import android.app.Activity;
import android.content.Context;
import android.graphics.Bitmap;
import android.util.Log;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.BaseAdapter;
import android.widget.ImageView;
import android.widget.TextView;
//For more information look at the bottom of file.
public class LazyAdapter extends BaseAdapter {
private Activity activity;
private String[] data;
private ArrayList<String> name;
private ArrayList<String> info;
private static LayoutInflater inflater=null;
public ImageLoader imageLoader;
private Bitmap b;
public LazyAdapter(Activity a, Bitmap d, ArrayList<String> names, ArrayList<String> information) {
activity = a;
b=d;
name=names;
info = information;
inflater = (LayoutInflater)activity.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
imageLoader=new ImageLoader(activity.getApplicationContext());
}
public int getCount() {
return name.size();
}
public Object getItem(int position) {
return position;
}
public long getItemId(int position) {
return position;
}
public static class ViewHolder{
public TextView name,info;
public ImageView image;
}
public View getView(int position, View convertView, ViewGroup parent) {
View vi=convertView;
ViewHolder holder;
if(convertView==null){
vi = inflater.inflate(R.layout.item, null);
holder=new ViewHolder();
holder.name=(TextView)vi.findViewById(R.id.name);
holder.info=(TextView)vi.findViewById(R.id.info);
holder.image=(ImageView)vi.findViewById(R.id.image);
vi.setTag(holder);
Log.v("Position","Position : "+position);
}
else
holder=(ViewHolder)vi.getTag();
holder.name.setText(name.get(position));
holder.info.setText(info.get(info.size()-1));
//Here I must do a black magic and get the images if user had 'em.
holder.image.setImageBitmap(b);
//holder.image.setTag(data[position]);
//imageLoader.DisplayImage(data[position], activity, holder.image);
// Black magic over.
return vi;
}
}
有什么想法或建议来完成这件事吗?