使用YQL将Yahoo!天气API数据返回为摄氏度

Question

我正在尝试获取以摄氏度为单位的Yahoo!天气API。

我在请求中添加了&u=c，但它仍然返回华氏温度数据。

这是我使用的URL:

http://query.yahooapis.com/v1/public/yql?q=select%20item%20from%20weather.forecast%20where%20location=%22LEXX0003%22&format=json&u=c

响应如下：

{"query":{"count":1,"created":"2014-01-13T13:06:43Z","lang":"en-US","results":{"channel":{"item":{"title":"Conditions for Beirut, LE at 1:59 pm EET","lat":"33.82","long":"35.48","link":"http://us.rd.yahoo.com/dailynews/rss/weather/Beirut__LE/*http://weather.yahoo.com/forecast/LEXX0003_f.html","pubDate":"Mon, 13 Jan 2014 1:59 pm EET","condition":{"code":"30","date":"Mon, 13 Jan 2014 1:59 pm EET","temp":"64","text":"Partly Cloudy"},"description":"\n<img src=\"http://l.yimg.com/a/i/us/we/52/30.gif\"/><br />\n<b>Current Conditions:</b><br />\nPartly Cloudy, 64 F<BR />\n<BR /><b>Forecast:</b><BR />\nMon - Partly Cloudy. High: 64 Low: 55<br />\nTue - Cloudy. High: 66 Low: 56<br />\nWed - Mostly Sunny. High: 68 Low: 58<br />\nThu - Sunny. High: 70 Low: 60<br />\nFri - Scattered Showers. High: 65 Low: 57<br />\n<br />\n<a href=\"http://us.rd.yahoo.com/dailynews/rss/weather/Beirut__LE/*http://weather.yahoo.com/forecast/LEXX0003_f.html\">Full Forecast at Yahoo! Weather</a><BR/><BR/>\n(provided by <a href=\"http://www.weather.com\" >The Weather Channel</a>)<br/>\n","forecast":[{"code":"30","date":"13 Jan 2014","day":"Mon","high":"64","low":"55","text":"Partly Cloudy"},{"code":"26","date":"14 Jan 2014","day":"Tue","high":"66","low":"56","text":"Cloudy"},{"code":"34","date":"15 Jan 2014","day":"Wed","high":"68","low":"58","text":"Mostly Sunny"},{"code":"32","date":"16 Jan 2014","day":"Thu","high":"70","low":"60","text":"Sunny"},{"code":"39","date":"17 Jan 2014","day":"Fri","high":"65","low":"57","text":"Scattered Showers"}],"guid":{"isPermaLink":"false","content":"LEXX0003_2014_01_17_7_00_EET"}}}}}}`

有任何想法吗？

- Kodr.F

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你解决了这个问题吗？ - DanV

Answer 1

迟到总比不到好...

var locationQuery = escape("select item from weather.forecast where woeid in (select woeid from geo.places where text='GB-LND') and u='c'"),
    locationUrl = "http://query.yahooapis.com/v1/public/yql?q=" + locationQuery + "&format=json&callback=?";

如果你把它拆开看会更容易理解。你已经很接近了，只需要将“u=c”作为查询的一部分，而不是放在URL的结尾。

- DanV

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u='c' 对我不起作用...它仍然以 F 的结果返回给我。 - H Raval

对我来说，u="c" 起作用了，而不是 u='c'。 - eadmaster

Answer 2

我使用了yql

select item from weather.forecast where woeid=22724447 and u='c'

它与摄氏度下的结果良好运作。我将“LEXX0003”更改为该区域的真实WOEID，似乎已经奏效。

- Aris

Answer 3

你可以尝试这个：

YQL查询：

select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="jiangmen,cn") and u="c"

终端点:

https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20weather.forecast%20where%20woeid%20in%20(select%20woeid%20from%20geo.places(1)%20where%20text%3D%22jiangmen%2Ccn%22)%20and%20u%3D%22c%22&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys

我刚刚尝试时这个有效

- Zhao Weihao

Answer 4

每当我需要将温度转换为摄氏度时，我只需使用一个简单的转换函数：

function FtoC(temp) {return Math.round((temp - 32) / (9 / 5));}

再说一遍，我想要在华氏度和摄氏度之间切换。如果你只想使用摄氏度，那么从雅虎调用摄氏度的JSON元素可能更好。

- Michael Howard

Answer 5

只需这样做，确保它能正常工作

在YQL查询的末尾添加-->{ and u="c" }

例如：

YQL查询

select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="greenland") and u="c"

- Helia Fathi