PHP - 使用ajax提交表单，并返回XML

Question

我有困难使用jQuery/AJAX提交表单，并返回一个成功消息和XML文件（在PHP中生成）。

这是我现在拥有的：

invoice.php：

<form method="post" id="invoiceform">
<? /* Populate the form with input later on. For now, the XML data is hardcoded in PHP */ ?>
<button type="submit">Submit form</button>
</form>


//Submit the form:
$('#invoiceform').on('submit', function(e) { //use on if jQuery 1.7+
    e.preventDefault();  //prevent form from submitting
    e.stopImmediatePropagation(); //prevent double.

    //Show the loading message.
    $form = $(this);

     // Use Ajax to submit form data
        $.ajax({
            url: '/api/invoice/invoice_converter',
            type: 'POST',
            data: $form.serialize(),
            dataType: "json",
            success: function(data) {

                            console.log(data);

                if (data.result == 'success') {
                //Success
                $(".status").html(data.message);

            } else {
                $(".status").html(data.message);
           }
        },
        error: function(data) {
            console.log("Something went wrong!");
            console.log(data);

        }
    });

return false;

});

好的，以上代码将简单地提交表单到下面的页面：

invoice_converter.php：

$invoice = new Invoice;
if($_POST)
{
    $convertInvoice = $invoice->convertInvoice();

    if($convertInvoice == 1){
              $error = "Error: Error message goes here.";
              $stop = true;
    }
    if($stop){
        $result = array("result" => "error","message" => $error);
    }else{

        $result = array("result" => "success","message" => $convertInvoice);

    }

}
header('Content-type: application/json');
echo json_encode($result);

所以，上述页面处理返回消息。实际的XML生成函数位于下面的页面中：functions.php:

function convertInvoice(){

    /* create a dom document with encoding utf8 */
      $domtree = new DOMDocument('1.0', 'UTF-8');

      /* create the root element of the xml tree */
      $xmlRoot = $domtree->createElement("xml");
      /* append it to the document created */
      $xmlRoot = $domtree->appendChild($xmlRoot);

      $currentTrack = $domtree->createElement("track");
      $currentTrack = $xmlRoot->appendChild($currentTrack);

      /* you should enclose the following two lines in a cicle */
      $currentTrack->appendChild($domtree->createElement('charge','letter'));
      $currentTrack->appendChild($domtree->createElement('description','Payable cover letters'));

      $currentTrack->appendChild($domtree->createElement('charge','vat'));
      $currentTrack->appendChild($domtree->createElement('description','Payable VAT'));

      /* get the xml printed */
      $xml =  $domtree->saveXML();

      return $xml;
}

从上面的console.log返回的数据如下：

<?xml version="1.0" encoding="UTF-8"?>
<xml>
  <track>
    <charge>letter</ charge >
    <description>Payable cover letters</ description >
    <charge>vat</ charge >
    <description>Payable VAT</ description >
   </track>
</xml>

虽然这是正确的，但我希望能够将上述内容“保存”为XML文件，并使其可供用户下载。

- oliverbj

---

您可以查看fwrite及其相关函数来进行写入操作，以及此答案来实现用户下载。 - Kyrre

Answer 1

你需要创建一个可写文件并将$xml写入文件。
此代码创建track.xml并向文档插入下载链接。

使用fopen以写入模式打开文件（如果不存在则创建），然后使用fwrite将内容写入文件，最后使用fclose关闭文件。文件必须放置在公共目录中，以确保Web服务器可以访问它。

// Open file and write contents
$file = fopen('track.xml', 'w+');
fwrite($file, $xml);
fclose($file);

// Generate download link
echo '<a href="/path/to/track.xml" download>Download</a>';

注意：您需要确保输出目录可被PHP写入，方法如下：

chown www-data:www-data /var/www/path/to/output
chmod 775 /var/www/path/to/output

- TheMisir