使用正则表达式在JS中将大型字符串文字解析为对象数组

Question

使用正则表达式在JS中将大型字符串文字解析为对象数组

4

我是新手程序员，但我正在努力学习JavaScript。目前，我正在开展一个项目，尝试将一个大文本文件（莎士比亚的154首十四行诗在这里）解析到对象数组中，数据结构如下：

var obj = {
property 1: [ 'value 1',
     'value 2',
    ], 
property 2: [ 'value 1',
     'value 2',
    ],

在这里，罗马数字代表对象属性，每行十四行诗分别代表每个属性数组中的一个值。

我必须使用正则表达式来解析文本文件。到目前为止，我一直在寻找正确的正则表达式来划分文本，但我不知道是否正确。最终我想创建一个下拉菜单，其中列表中的每个值都是一个十四行诗。

编辑：实际上我现在从这个网址获取源文本：http://pizzaboys.biz/xxx/sonnets.php

然后做与上面相同的事情，但不是用 $get，而是将文本放入变量中...

我尝试过这样：

$(document).ready(function(){
    var data = new SonnetizerArray();
});

function SonnetizerArray(){
    this.data = [];
    var rawText = "text from above link"
    var rx = /^\\n[CDILVX]/$\\n/g;

    var array_of_sonnets = rawText.exec(rx);
    for (var i = 0; i < array_of_sonnets.length; i ++){
        var s = $.split(array_of_sonnets[i]);
        if (s.length > 0) this.data.push(s);
    }
}

- Jake

3

好的，请展示一下你目前发现或尝试过的内容。你可能已经接近成功，也可能不是；我们不知道你的尝试。 - Ian

刚刚将其添加到原始内容中。 - Jake

1个回答

网页内容由stack overflow 提供, 点击上面的

可以查看英文原文，
原文链接

- Ro Yo Mi · Accepted Answer

描述

这个正则表达式将文本解析为罗马数字和正文。然后可以在换行符\n上对正文进行拆分。

^\s+\b([CDMLXVI]{1,12})\b(?:\r|\n|$).*?(?:^.*?)(^.*?)(?=^\s+\b([MLXVI]{1,12})\b(?:\r|\n|$)|\Z)

enter image description here

捕获组

组0获取整个匹配部分

获取罗马数字
获取章节内容，不包括罗马数字

Javascript代码示例：

从您的链接中提取的示例文本

  VII

  Lo! in the orient when the gracious light
  Lifts up his burning head, each under eye
  Doth homage to his new-appearing sight,


  VIII

  Music to hear, why hear'st thou music sadly?
  Sweets with sweets war not, joy delights in joy:
  Why lov'st thou that which thou receiv'st not gladly,
  Or else receiv'st with pleasure thine annoy?


  IX

  Is it for fear to wet a widow's eye,
  That thou consum'st thy self in single life?
  Ah! if thou issueless shalt hap to die,
  The world will wail thee like a makeless wife;

示例代码

<script type="text/javascript">
  var re = /^\s+\b([MLXVI]{1,12})\b(?:\r|\n|$).*?(?:^.*?)(^.*?)(?=^\s+\b([MLXVI]{1,12})\b(?:\r|\n|$)|\Z)/;
  var sourcestring = "source string to match with pattern";
  var results = [];
  var i = 0;
  for (var matches = re.exec(sourcestring); matches != null; matches = re.exec(sourcestring)) {
    results[i] = matches;
    for (var j=0; j<matches.length; j++) {
      alert("results["+i+"]["+j+"] = " + results[i][j]);
    }
    i++;
  }
</script>

样例输出

$matches Array:
(
    [0] => Array
        (
            [0] =>   VII

  Lo! in the orient when the gracious light
  Lifts up his burning head, each under eye
  Doth homage to his new-appearing sight,

            [1] => 

  VIII

  Music to hear, why hear'st thou music sadly?
  Sweets with sweets war not, joy delights in joy:
  Why lov'st thou that which thou receiv'st not gladly,
  Or else receiv'st with pleasure thine annoy?

            [2] => 

  IX

  Is it for fear to wet a widow's eye,
  That thou consum'st thy self in single life?
  Ah! if thou issueless shalt hap to die,
  The world will wail thee like a makeless wife;
        )

    [1] => Array
        (
            [0] => VII
            [1] => VIII
            [2] => IX
        )

    [2] => Array
        (
            [0] => 
  Lo! in the orient when the gracious light
  Lifts up his burning head, each under eye
  Doth homage to his new-appearing sight,

            [1] => 
  Music to hear, why hear'st thou music sadly?
  Sweets with sweets war not, joy delights in joy:
  Why lov'st thou that which thou receiv'st not gladly,
  Or else receiv'st with pleasure thine annoy?

            [2] => 
  Is it for fear to wet a widow's eye,
  That thou consum'st thy self in single life?
  Ah! if thou issueless shalt hap to die,
  The world will wail thee like a makeless wife;
        )

    [3] => Array
        (
            [0] => VIII
            [1] => IX
            [2] => 
        )

)

罗马数字验证

上述表达式仅测试罗马数字字符串是否由罗马数字字符组成，它并不能验证该数字是否有效。如果您需要验证罗马数字的格式是否正确，那么可以使用以下表达式。

^\s+\b(M{0,4}(CM|CD|D?C{0,3})(XC|XL|L?X{0,3})(IX|IV|V?I{0,3}))\b(?:\r|\n|$).*?(?:^.*?)(^.*?)(?=^\s+\b([MLXVI]{1,12})\b(?:\r|\n|$)|\Z)

enter image description here