$search=array("<",">","!=","<=",">=")
$value="name >= vivek ";
我想检查$value是否包含$search数组中的任何一个值。我可以使用foreach和strpos函数来找到答案。如果不使用foreach，我还能找到答案吗？如果可以，请帮助我解决这个问题。
6个回答
2
将$value爆炸成数组，然后使用php中的array_intersect()函数来检查字符串是否不包含数组的值。使用下面的代码：
<?php
$search=array("<",">","!=","<=",">=");
$value='name >= vivek ';
$array = explode(" ",$value);
$p = array_intersect($search,$array);
$errors = array_filter($p);
//Check if the string is not empty
if(!empty($errors)){
echo "The string contains an value of array";
}
else
{
echo "The string does not containe the value of an array";
}
?>
在这里测试代码http://sandbox.onlinephpfunctions.com/code/7e65faf808de77036a83e185050d0895553d8211
希望这能帮到你
- Utkarsh Dixit
0
是的，但这将需要您重新构建您的代码。
$search = array("<" => 0, ">" => 1,"!=" => 2,"<=" => 3,">=" => 4);
$value = "name => vivek ";
$value = explode(" ", $value);
foreach($value as $val) {
// search the array in O(1) time
if(isset($search[$val])) {
// found a match
}
}
- Ryan
0
使用 array_map() 和 array_filter()。
function cube($n)
{
$value="name => vivek ";
return strpos($value, $n);
//return($n * $n * $n);
}
$a = array("<",">","!=","<=",">=");
$value="name => vivek ";
$b = array_map("cube", $a);
print_r($b);
$b = array_filter($b);
print_r($b);
- Pupil
1
1
array_filter 接受一个回调函数，这里不需要使用 array_map。 - ccKep0
$search = array("<",">","!=","<=",">=");
$value="name => vivek ";
foreach($value as $searchval) {
if(strpos($value, $searchval) == false)
{
echo "match not found";
}
else
{
echo "match found";
}
}
- user3040610
0
以下是使用array_reduce的解决方案：
<?PHP
function array_in_string_callback($carry, $item)
{
list($str, $found) = $carry;
echo $str . " - " . $found . " - " . $str . " - " . $item . "<br/>";
$found |= strpos($str, $item);
return array($str, (boolean) $found);
}
function array_in_string($haystack, $needle)
{
$retVal = array_reduce($needle, "array_in_string_callback", array($haystack, false));
return $retVal[1];
}
$search=array("<",">","!=","<=",">=");
$value="name >= vivek ";
var_dump(array_in_string($value, $search));
?>
- ccKep
0
我的第一反应是使用array_walk()和回调函数来解决问题，如下所示：
<?php
$search=array("<",">","!=","<=",">=");
$value = "name >= vivek ";
function test($item, $key, $str)
{
if( strpos($str, $item) !== FALSE ) {
echo "$item found in \"$str\"\n";
}
}
array_walk($search, 'test', $value);
// output:
> found in "name >= vivek "
>= found in "name >= vivek "
虽然这种方法可以不使用foreach循环解决问题，但它的回答是“什么”，而不是“是/否”。以下代码直接回答了问题，并允许回答“什么”，如下：
<?php
function test($x)
{
$value="name >= vivek ";
return strpos($value, $x);
}
$search = array("<",">","!=","<=",">=");
$chars = array_filter( $search, "test" );
$count = count($chars);
echo "Are there any search chars? ", $answer = ($count > 0)? 'Yes, as follows: ' : 'No.';
echo join(" ",$chars);
// output:
Are there any search chars? Yes, as follows: > >=
如果响应为否定，则输出为“否”后跟一个空格。
与第一种解决方案相比，第二种解决方案的关键区别在于，在这种情况下有一个可以操作的返回结果。如果数组的元素与字符串中的字符匹配，则array_filter将该元素添加到$chars中。新数组的元素计数回答了问题，而数组本身包含任何匹配项，如果希望显示它们。
- slevy1
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