function QueryStringBuilder() {
var nameValues = [];
this.add = function(name, value) {
nameValues.push( {name: name, value: value} );
};
this.toQueryString = function() {
var segments = [], nameValue;
for (var i = 0, len = nameValues.length; i < len; i++) {
nameValue = nameValues[i];
segments[i] = encodeURIComponent(nameValue.name) + "=" + encodeURIComponent(nameValue.value);
}
return segments.join("&");
};
}
var qsb = new QueryStringBuilder();
qsb.add("veg", "cabbage");
qsb.add("vegCount", "5");
alert( qsb.toQueryString() );
objectToQueryString(obj, prefix) {
return Object.keys(obj).map(objKey => {
if (obj.hasOwnProperty(objKey)) {
const key = prefix ? `${prefix}[${objKey}]` : objKey;
const value = obj[objKey];
return typeof value === "object" ?
this.objectToQueryString(value, key) :
`${encodeURIComponent(key)}=${encodeURIComponent(value)}`;
}
return null;
}).join("&");
}
以下是被采纳答案的CoffeeScript版本。
serialize = (obj, prefix) ->
str = []
for p, v of obj
k = if prefix then prefix + "[" + p + "]" else p
if typeof v == "object"
str.push(serialize(v, k))
else
str.push(encodeURIComponent(k) + "=" + encodeURIComponent(v))
str.join("&")
使用:
const toQueryString = obj => "?".concat(Object.keys(obj).map(e => `${encodeURIComponent(e)}=${encodeURIComponent(obj[e])}`).join("&"));
const data = {
offset: 5,
limit: 10
};
toQueryString(data); // => ?offset=5&limit=10
const data = {
offset: 5,
limit: 10
};
new URLSearchParams(data).toString(); // => ?offset=5&limit=10
如果未出现在上述方法中,它们都会将值设置为 null。 如果您希望在值为 null 时不设置查询参数,则使用以下方法:
const toQueryString = obj => "?".concat(Object.keys(obj).map(e => obj[e] ? `${encodeURIComponent(e)}=${encodeURIComponent(obj[e])}` : null).filter(e => !!e).join("&"));
const data = {
offset: null,
limit: 10
};
toQueryString(data); // => "?limit=10" else with above methods "?offset=null&limit=10"
您可以自由使用任何方法。
export function urlEncodeQueryParams(data) {
const params = Object.keys(data).map(key => data[key] ? `${encodeURIComponent(key)}=${encodeURIComponent(data[key])}` : '');
return params.filter(value => !!value).join('&');
}
这里是一个简洁且递归的版本,使用Object.entries。它可以处理任意嵌套的数组,但不能处理嵌套的对象。同时也会删除空元素:
const format = (k,v) => v !== null ? `${k}=${encodeURIComponent(v)}` : ''
const to_qs = (obj) => {
return [].concat(...Object.entries(obj)
.map(([k,v]) => Array.isArray(v)
? v.map(arr => to_qs({[k]:arr}))
: format(k,v)))
.filter(x => x)
.join('&');
}
E.g.:
let json = {
a: [1, 2, 3],
b: [], // omit b
c: 1,
d: "test&encoding", // uriencode
e: [[4,5],[6,7]], // flatten this
f: null, // omit nulls
g: 0
};
let qs = to_qs(json)
=> "a=1&a=2&a=3&c=1&d=test%26encoding&e=4&e=5&e=6&e=7&g=0"
我有一个更简单的解决方案,不使用任何第三方库,并且已经适用于任何具有“Object.keys”(即所有现代浏览器+Edge + Internet Explorer)的浏览器:
在ES5中:
function(a){
if( typeof(a) !== 'object' )
return '';
return `?${Object.keys(a).map(k=>`${k}=${a[k]}`).join('&')}`;
}
在ES3中:
function(a){
if( typeof(a) !== 'object' )
return '';
return '?' + Object.keys(a).map(function(k){ return k + '=' + a[k] }).join('&');
}
我做了一个JSON字符串化器的比较,结果如下:
JSON: {"_id":"5973782bdb9a930533b05cb2","isActive":true,"balance":"$1,446.35","age":32,"name":"Logan Keller","email":"logankeller@artiq.com","phone":"+1 (952) 533-2258","friends":[{"id":0,"name":"Colon Salazar"},{"id":1,"name":"French Mcneil"},{"id":2,"name":"Carol Martin"}],"favoriteFruit":"banana"}
Rison: (_id:'5973782bdb9a930533b05cb2',age:32,balance:'$1,446.35',email:'logankeller@artiq.com',favoriteFruit:banana,friends:!((id:0,name:'Colon Salazar'),(id:1,name:'French Mcneil'),(id:2,name:'Carol Martin')),isActive:!t,name:'Logan Keller',phone:'+1 (952) 533-2258')
O-Rison: _id:'5973782bdb9a930533b05cb2',age:32,balance:'$1,446.35',email:'logankeller@artiq.com',favoriteFruit:banana,friends:!((id:0,name:'Colon Salazar'),(id:1,name:'French Mcneil'),(id:2,name:'Carol Martin')),isActive:!t,name:'Logan Keller',phone:'+1 (952) 533-2258'
JSURL: ~(_id~'5973782bdb9a930533b05cb2~isActive~true~balance~'!1*2c446.35~age~32~name~'Logan*20Keller~email~'logankeller*40artiq.com~phone~'*2b1*20*28952*29*20533-2258~friends~(~(id~0~name~'Colon*20Salazar)~(id~1~name~'French*20Mcneil)~(id~2~name~'Carol*20Martin))~favoriteFruit~'banana)
QS: _id=5973782bdb9a930533b05cb2&isActive=true&balance=$1,446.35&age=32&name=Logan Keller&email=logankeller@artiq.com&phone=+1 (952) 533-2258&friends[0][id]=0&friends[0][name]=Colon Salazar&friends[1][id]=1&friends[1][name]=French Mcneil&friends[2][id]=2&friends[2][name]=Carol Martin&favoriteFruit=banana
URLON: $_id=5973782bdb9a930533b05cb2&isActive:true&balance=$1,446.35&age:32&name=Logan%20Keller&email=logankeller@artiq.com&phone=+1%20(952)%20533-2258&friends@$id:0&name=Colon%20Salazar;&$id:1&name=French%20Mcneil;&$id:2&name=Carol%20Martin;;&favoriteFruit=banana
QS-JSON: isActive=true&balance=%241%2C446.35&age=32&name=Logan+Keller&email=logankeller%40artiq.com&phone=%2B1+(952)+533-2258&friends(0).id=0&friends(0).name=Colon+Salazar&friends(1).id=1&friends(1).name=French+Mcneil&friends(2).id=2&friends(2).name=Carol+Martin&favoriteFruit=banana
还有另一个流行的库qs。你可以通过以下方式添加它:
yarn add qs
然后像这样使用它:
import qs from 'qs'
const array = { a: { b: 'c' } }
const stringified = qs.stringify(array, { encode: false })
console.log(stringified) //-- outputs a[b]=c
let Objs = { a: 'obejct-a', b: 'object-b' }
Object.keys(objs).map(key => key + '=' + objs[key]).join('&')
// The result will be a=object-a&b=object-b