KINWebBrowser是一个开源的iOS应用程序浏览器模块。我最近升级了KINWebBrowser,使用WKWebView来逐步淘汰UIWebView。这样可以显著提高性能,但是:
问题: WKWebView不支持启动包含电话号码、电子邮件地址、地图等URL的链接。
如何配置WKWebView,在从页面中启动这些替代URL链接时,以启动标准的iOS行为?
更多关于WKWebKit的信息
KINWebBrowser是一个开源的iOS应用程序浏览器模块。我最近升级了KINWebBrowser,使用WKWebView来逐步淘汰UIWebView。这样可以显著提高性能,但是:
问题: WKWebView不支持启动包含电话号码、电子邮件地址、地图等URL的链接。
如何配置WKWebView,在从页面中启动这些替代URL链接时,以启动标准的iOS行为?
更多关于WKWebKit的信息
通过将此函数添加到KINWebBrowserViewController.m中,我成功让Google Maps链接(似乎与target="_blank"相关)和tel:方案正常工作。
- (void)webView:(WKWebView *)webView decidePolicyForNavigationAction:(WKNavigationAction *)navigationAction decisionHandler:(void (^)(WKNavigationActionPolicy))decisionHandler
{
if(webView != self.wkWebView) {
decisionHandler(WKNavigationActionPolicyAllow);
return;
}
UIApplication *app = [UIApplication sharedApplication];
NSURL *url = navigationAction.request.URL;
if (!navigationAction.targetFrame) {
if ([app canOpenURL:url]) {
[app openURL:url];
decisionHandler(WKNavigationActionPolicyCancel);
return;
}
}
if ([url.scheme isEqualToString:@"tel"])
{
if ([app canOpenURL:url])
{
[app openURL:url];
decisionHandler(WKNavigationActionPolicyCancel);
return;
}
}
decisionHandler(WKNavigationActionPolicyAllow);
}
decisionHandler
。 - Aaron Brager适用于xcode 8.1和Swift 2.3。
针对"_blank"、电话号码(tel:)和电子邮件(mailto:)链接。
func webView(webView: WKWebView, decidePolicyForNavigationAction navigationAction: WKNavigationAction, decisionHandler: (WKNavigationActionPolicy) -> Void) {
if webView != self.webview {
decisionHandler(.Allow)
return
}
let app = UIApplication.sharedApplication()
if let url = navigationAction.request.URL {
// Handle target="_blank"
if navigationAction.targetFrame == nil {
if app.canOpenURL(url) {
app.openURL(url)
decisionHandler(.Cancel)
return
}
}
// Handle phone and email links
if url.scheme == "tel" || url.scheme == "mailto" {
if app.canOpenURL(url) {
app.openURL(url)
decisionHandler(.Cancel)
return
}
}
decisionHandler(.Allow)
}
}
更新了Swift 4.0
func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
if webView != self.webView {
decisionHandler(.allow)
return
}
let app = UIApplication.shared
if let url = navigationAction.request.url {
// Handle target="_blank"
if navigationAction.targetFrame == nil {
if app.canOpenURL(url) {
app.open(url)
decisionHandler(.cancel)
return
}
}
// Handle phone and email links
if url.scheme == "tel" || url.scheme == "mailto" {
if app.canOpenURL(url) {
app.open(url)
}
decisionHandler(.cancel)
return
}
decisionHandler(.allow)
}
}
您需要实现另一个回调函数以正确获取此内容(Swift 5.0):
// Gets called if webView cant handle URL
func webView(_ webView: WKWebView, didFailProvisionalNavigation navigation: WKNavigation!, withError error: Error) {
guard let failingUrlStr = (error as NSError).userInfo["NSErrorFailingURLStringKey"] as? String else { return }
let failingUrl = URL(string: failingUrlStr)!
switch failingUrl {
// Needed to open Facebook
case _ where failingUrlStr.hasPrefix("fb:"):
if #available(iOS 10.0, *) {
UIApplication.shared.open(failingUrl, options: [:], completionHandler: nil)
return
} // Else: Do nothing, iOS 9 and earlier will handle this
// Needed to open Mail-app
case _ where failingUrlStr.hasPrefix("mailto:"):
if UIApplication.shared.canOpenURL(failingUrl) {
UIApplication.shared.open(failingUrl, options: [:], completionHandler: nil)
return
}
// Needed to open Appstore-App
case _ where failingUrlStr.hasPrefix("itmss://itunes.apple.com/"):
if UIApplication.shared.canOpenURL(failingUrl) {
UIApplication.shared.open(failingUrl, options: [:], completionHandler: nil)
return
}
default: break
}
}
我是在搜索如何在wkwebview上打开gmail附件时来到这里的。
我的解决方案很简单:
func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
if navigationAction.targetFrame == nil, let redirect = navigationAction.request.url {
if UIApplication.shared.canOpenURL(redirect) {
self.webViewMail?.load(navigationAction.request)
decisionHandler(.cancel)
return
}
}
decisionHandler(.allow)
}
这对我在Xcode 8 WKWebview中很有帮助
func webView(_ webView: WKWebView, createWebViewWith configuration: WKWebViewConfiguration, for navigationAction: WKNavigationAction, windowFeatures: WKWindowFeatures) -> WKWebView? {
if navigationAction.targetFrame == nil {
let url = navigationAction.request.url
if url?.description.range(of: "http://") != nil || url?.description.range(of: "https://") != nil || url?.description.range(of: "mailto:") != nil || url?.description.range(of: "tel:") != nil {
UIApplication.shared.openURL(url!)
}
}
return nil
}
编辑:
链接中必须包含属性target="_blank"
。
Swift 4.2 更新
抱歉挖出一个旧帖子,但我遇到了同样的问题,并更新了 Swift 4.2 的解决方案。我将我的解决方案放在这里,以便它可以帮助其他人,如果不能,我希望下次使用 WKWebView 时能找到它!
func webView(_ webView: WKWebView, decidePolicyFor navigationAction: WKNavigationAction, decisionHandler: @escaping (WKNavigationActionPolicy) -> Void) {
let url = navigationAction.request.url?.absoluteString
let urlElements = url?.components(separatedBy: ":") ?? []
switch urlElements[0] {
case "tel":
UIApplication.shared.openURL(navigationAction.request.url!)
decisionHandler(.cancel)
case "mailto":
UIApplication.shared.openURL(navigationAction.request.url!)
decisionHandler(.cancel)
default:
decisionHandler(.allow)
}
}
SubzDesignz iOS Swift 4 WKWebview – Detect tel, mailto, target=”_blank” and CheckConnection
上面的答案对我有用,但我需要将其重写为Swift 2.3
if navigationAction.targetFrame == nil {
let url = navigationAction.request.mainDocumentURL
if url?.description.rangeOfString("mailto:")?.startIndex != nil ||
url?.description.rangeOfString("tel:")?.startIndex != nil
{
if #available(iOS 10, *) {
UIApplication.sharedApplication().openURL(url!,options: [:], completionHandler: nil)
} else {
UIApplication.sharedApplication().openURL(url!) // deprecated
}
}
}