我有一个如下所示的Json对象。我想要访问adult
的值。但是当我做echo json_decode($json_response, true);
时,我得到了Array to string conversion
的错误提示。这里出了什么问题?
{
"responses": [
{
"safeSearchAnnotation": {
"adult": "VERY_UNLIKELY",
"spoof": "VERY_UNLIKELY",
"medical": "UNLIKELY",
"violence": "LIKELY"
}
}
]
}