我有一个类似于字典的数据结构:
{
"checksum": "b884cbfb1a6697fa9b9eea9cb2054183",
"roots": {
"bookmark_bar": {
"children": [ {
"date_added": "12989159740428363",
"id": "4",
"name": "test2",
"type": "url",
"url": "chrome://bookmarks/#1"
} ],
"date_added": "12989159700896551",
"date_modified": "12989159740428363",
"id": "1",
"name": "bookmark_bar",
"type": "folder"
},
"other": {
"children": [ {
"date_added": "12989159740428363",
"id": "4",
"name": "test",
"type": "url",
"url": "chrome://bookmarks/#1"
} ],
"date_added": "12989159700896557",
"date_modified": "0",
"id": "2",
"name": "aaa",
"type": "folder"
},
"synced": {
"children": [ ],
"date_added": "12989159700896558",
"date_modified": "0",
"id": "3",
"name": "bbb",
"type": "folder"
}
},
"version": 1
}
一切都始于“根”,它们有两种类型的数据:URL和文件夹,它们都是字典。
如果是文件夹,则必须具有键'children',该键的值为列表,我们可以在其中添加更多的URL和文件夹。
现在我想遍历这个嵌套字典,以获取所有子文件夹中的URL,因此我编写了一个函数:
def traverse(dic):
for i in dic:
if i['type'] == 'folder':
for j in traverse(i['children']):
yield j
elif i['type'] == 'url':
yield i
我可以这样使用它:
traverse(dictionary['roots']['bookmark_bar']['children'])
它完美地工作了。但它只生成了一个URL的字典,我不知道它在哪里。 我想要获取路径。我该怎么做?