Django - 翻译Permission模型的名称

Question

我试图翻译权限的名称，但是这段代码没有起作用。我没有收到任何错误消息，权限仍然是英文的，我希望它们能够使用设置中设定的语言。你有什么想法吗？

# forms.py
from django.utils.translation import gettext as _
class PermissionModelMultipleChoiceField(forms.ModelMultipleChoiceField):
def label_from_instance(self, obj):
    return '%s' % _(obj.name)

# settings.py
LANGUAGE_CODE = 'pt-br'
USE_I18N = True
USE_L10N = True

- Dev Python

---

你好，这个回答能帮到你吗？这里是链接。 - mh-firouzjah

Answer 1

我能够手动翻译权限的名称。一些像"Can"这样的单词无法通过gettext_lazy进行翻译，所以我使用了"replace"方法来保留我想要的语言。其他像"group"或"user"这样的单词可以通过gettext_lazy进行翻译。

# forms.py
from django import forms
from django.utils.translation import gettext_lazy as _

class PermissionModelMultipleChoiceField(forms.ModelMultipleChoiceField):
def label_from_instance(self, obj):
    permissions_translated = [_(w).replace('Can', 'Pode').replace('add', 'adicionar').replace('change', 'alterar').replace('delete', 'excluir').replace('view', 'visualizar') for w in (obj.name).split()]
    return ' '.join(permissions_translated)

- Dev Python

---

嗨，你能不能看一下这个答案。 - mh-firouzjah

Answer 2

这段代码片段可以帮助你。

class RoleCreateForm(forms.ModelForm):
    permissions = forms.ModelMultipleChoiceField(
        queryset=Permission.objects.none(),
        widget=forms.SelectMultiple(attrs={
            'class':'selectpicker widget border border-2 border-warning rounded bg-transparent'
        })
    )

    class Meta:
        model = Group
        fields = "__all__"

        widgets={
            'name':forms.TextInput(attrs={
                'class':'form-control widget border-warning rounded'
            })
        }

    def __init__(self, *args, **kwargs):
        super().__init__(*args, **kwargs)

        # Filter permissions for tracking, traccar, and accounts apps
        tracking_permissions = Permission.objects.filter(content_type__app_label='tracking').exclude(content_type__model='geoeventsetting')
        traccar_permissions = Permission.objects.filter(content_type__app_label='traccar', content_type__model__in=['tcdevices', 'tcreports'])
        accounts_permissions = Permission.objects.filter(content_type__app_label='accounts',content_type__model__in=['useraccount'])
        auth_permissions = Permission.objects.filter(content_type__app_label='auth',content_type__model__in=['group'])

        # Concatenate the filtered permissions and set them as the choices for the permissions field
        self.fields['permissions'].queryset = tracking_permissions | traccar_permissions | accounts_permissions |auth_permissions

        # Translate the permission names
        self.fields['permissions'].label_from_instance = self.label_permission_instance

    def label_permission_instance(self, obj):
        permission_name = obj.name


        permissions_translated =[w.replace('Can', 'Peut').replace('add', 'ajouter').replace('change', 'modifier').replace('delete', 'supprimer').replace('view', 'voir').replace('user', 'utilisateur').replace('tc', '').replace('devices', 'boitiers').replace('reports', 'rapports').replace('group', 'profil')   for w in permission_name.split()]
        return ' '.join(permissions_translated)

- Muhammadoufi

Answer 3

你可以为Permission模型重写__str__方法。

from django.contrib.auth.models import Permission

def permission_string_method(self):
    names = self.name.split()
    operation_translated = ' '.join([
        _(w).replace('Can', str(_('Can')))
        .replace('add', str(_('add')))
        .replace('change', str(_('change')))
        .replace('delete', str(_('delete')))
        .replace('view', str(_('view')))
        .replace('log', '').replace('content', '').strip()
        for w in names[:-1]  # Exclude the last word (model name)
    ])
    return f"{operation_translated} | {self.content_type.name}"

Permission.__str__ = permission_string_method

将您的翻译放入django.po文件中。

msgid "Can"
msgstr "Pode"
msgid "view"
msgstr "visualizar"
msgid "add"
msgstr "adicionar"
msgid "change"
msgstr "alterar"
msgid "delete"
msgstr "excluir"

不要忘记运行 python manage.py compilemessages

- Sekiro