有没有办法在初始化类时避免调用
我试图创建一个Python中用于高效比较的不区分大小写和标点符号的字符串类,但是在创建新实例时无法避免调用
编辑:受下面答案的启发,初始化程序已经被编辑为快速检查无参数。
__init__
,比如从类方法中调用?我试图创建一个Python中用于高效比较的不区分大小写和标点符号的字符串类,但是在创建新实例时无法避免调用
__init__
。>>> class String:
def __init__(self, string):
self.__string = tuple(string.split())
self.__simple = tuple(self.__simple())
def __simple(self):
letter = lambda s: ''.join(filter(lambda s: 'a' <= s <= 'z', s))
return filter(bool, map(letter, map(str.lower, self.__string)))
def __eq__(self, other):
assert isinstance(other, String)
return self.__simple == other.__simple
def __getitem__(self, key):
assert isinstance(key, slice)
string = String()
string.__string = self.__string[key]
string.__simple = self.__simple[key]
return string
def __iter__(self):
return iter(self.__string)
>>> String('Hello, world!')[1:]
Traceback (most recent call last):
File "<pyshell#2>", line 1, in <module>
String('Hello, world!')[1:]
File "<pyshell#1>", line 17, in __getitem__
string = String()
TypeError: __init__() takes exactly 2 positional arguments (1 given)
>>>
我应该用什么替换string = String(); string.__string = self.__string[key]; string.__simple = self.__simple[key]
来初始化新对象的切片?编辑:受下面答案的启发,初始化程序已经被编辑为快速检查无参数。
def __init__(self, string=None):
if string is None:
self.__string = self.__simple = ()
else:
self.__string = tuple(string.split())
self.__simple = tuple(self.__simple())