我正在使用PyQt进行一个项目。但突然出现了以下错误:
QPixmap:在PyQt中,不安全地在GUI线程外部使用像素图
我没有在我的代码中使用QPixmap... 请帮忙。
class itemCheckBtn(QtGui.QDialog):
qApp = None;
okCallback = None;
def __init__(self,parent=None):
itemCheckBtn.qApp=None;
QtGui.QWidget.__init__(self, None)
self.ui = Ui_merchantPriceFrom();
self.ui.setupUi(self)
QtCore.QObject.connect(self.ui.itemCheckButton, QtCore.SIGNAL("clicked()"), self.submit)
def submit(self):
print "Hi";
主要的类是:
class MyForm(QtGui.QMainWindow):
serverThreadObject = None;
qApp = None;
sock = None;
def __init__(self, qApp,parent=None):
MyForm.qApp=qApp;
QtGui.QWidget.__init__(self, parent)
self.ui = Ui_bluwavemerchantmain()
self.ui.setupUi(self)
self.ui.server_connection_status_label.setText("Server Offline..");
QtCore.QObject.connect(self.ui.pushButton, QtCore.SIGNAL("clicked()"), self.connectUser )
QtCore.QObject.connect(self.ui.actionStart_Server, QtCore.SIGNAL("triggered()"), self.startServer);
QtCore.QObject.connect(self.ui.actionStop_Server, QtCore.SIGNAL("triggered()"), self.stopServerFromGui);
QtCore.QObject.connect(self.ui.actionExit, QtCore.SIGNAL("triggered()"), self.closeEventFromMenu);
QtCore.QObject.connect(self, QtCore.SIGNAL("triggered()"), self.closeEvent);
当我尝试从"MyForm"类调用"class itemCheckBtn"时,出现了错误。