我正在使用 Laravel 5.1
。
我有两个表,分别是users
和medicines
,它们之间存在多对多
的关系。相关的models
如下所示:
class User extends BaseModel {
use SoftDeletes;
protected $dates = ['deleted_at'];
protected $table = 'users';
public function medicines(){
return $this->belongsToMany('App\Models\Medicine')->withPivot('id', 'time','config' ,'start','end' );
}
}
并且。
class Medicine extends BaseModel{
use SoftDeletes;
protected $dates = ['deleted_at'];
protected $table = 'medicines';
public function users(){
return $this->belongsToMany('App\Models\User')->withPivot('id', 'time','config' ,'start','end' );
}
}
以下是具有一些额外的pivot列
的多对多
关系表user_medicine
:
id(PK) user_id(FK users) medicine_id(FK medicines) time config start end
1 1 41 09:00 {dispense:2} 2015-12-01 2015-12-25
2 1 43 10:00 {dispense:1} 2015-12-10 2015-12-22
3 1 44 17:00 NULL 2015-12-10 2015-12-31
现在,我想要更改特定药品的时间。我已经编写了以下代码:
public function updateMedicationTime($fields){
$result = array();
try {
$user = User::find($fields['user_id']);
$medicines = $user->medicines()->where('medicines.id',$fields['medicine_id'])->first();
if (!empty($medicines)){
$medicine_times = json_decode($medicines->pivot->time);
foreach ($medicine_times as $key=>$medicine_time ){
if ($medicine_time->time == $fields['oldtime']){
$medicine_time->time = $fields['newtime'];
}
}
// Update the time column of provided medicine id
$user->medicines()->where('medicines.id',$fields['medicine_id'])->sync(array($medicines->id , array("time"=>json_encode($medicine_times))), false);
// I also have tried
// $medicines->sync(array($medicines->id , array("time"=>json_encode($medicine_times))), false); OR
// $medicines->pivot->sync(array($medicines->id , array("time"=>json_encode($medicine_times))), false);
}
}
catch(Exception $e ){
throw $e;
}
return $result;
}
但是,与其更新现有的“多对多”表中的时间列,它会插入一条新记录,药品id = 1,并提供时间和其他列为null。有人能建议我在哪里犯了错误吗?