根据范围分配等级:
def getGrade(size):
grade =''
if size <= 32:
grade = 'p4'
elif size > 32 and size <=64:
grade = 'p6'
elif size > 64 and size <= 128:
grade = 'p10'
elif size > 128 and size <= 256:
grade = 'p15'
elif size > 256 and size <=512:
grade = 'p20'
elif size > 512 and size <= 1024:
grade = 'p30'
elif size > 1024 and size <= 2048:
grade = 'p40'
......
问题是需要再增加20个检查,是否有比这种方法更好的方式。
dict
,以range
对象 (作为键) 和成绩字符串 (作为值) 为元素? - UnholySheep32<size<=64
而不是size>32 and size<=64
。 - PM 2Ring