我有一个ScrollView,想要插入用户指定数量的HorizontalScrollView。当用户说他想要一个5x5元素的矩阵时,我想插入5个每个包含5个EditText对象的HorizontalScrollView。我的程序可以像应该的那样添加第一行,但是其他行不行。
for (int i = 0; i < number; i++) {
LinearLayout ll = new LinearLayout(this);
ll.setLayoutParams(par2);
HorizontalScrollView row = new HorizontalScrollView(this);
row.setLayoutParams(par1);
row.addView(ll);
for (int j = 0; j < number; j++) {
EditText txt = new EditText(this);
txt.setLayoutParams(new LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT));
txt.setHint(i+","+j);
ll.addView(txt);
}
latout_in_scrollview.addView(row);
}
有什么想法吗?感谢! 编辑: 我使用的是1:1代码。
LinearLayout dijkstra_rows;
FrameLayout.LayoutParams par1 = new FrameLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT);
LinearLayout.LayoutParams par2 = new LinearLayout.LayoutParams(LayoutParams.MATCH_PARENT, LayoutParams.WRAP_CONTENT);
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.layout_dijkstra);
dijkstra_rows = (LinearLayout) findViewById(R.id.dijkstra_rows);
Bundle extras = getIntent().getExtras();
number = extras.getInt("vertexes");
for (int i = 0; i < number; i++) {
LinearLayout ll = new LinearLayout(this);
ll.setLayoutParams(par2);
HorizontalScrollView row = new HorizontalScrollView(this);
row.setLayoutParams(par1);
row.addView(ll);
for (int j = 0; j < number; j++) {
EditText txt = new EditText(this);
txt.setLayoutParams(new LayoutParams(LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT));
txt.setHint(i+","+j);
ll.addView(txt);
}
dijkstra_rows.addView(row);
}
}