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如何从脚本中搜索 Stack Overflow 的问题？

pythonsearchscriptingstackexchange-api
5

给定一个关键词字符串，比如“Python最佳实践”，我想要从一个Python脚本中获取包含该关键词的前10个Stack Overflow问题，按相关性排序。我的目标是得到一个元组列表（标题，URL）。

我该如何实现这个目标？考虑查询谷歌吗？（你会如何用Python实现？）

5个回答
6
>>> from urllib import urlencode
>>> params = urlencode({'q': 'python best practices', 'sort': 'relevance'})
>>> params
'q=python+best+practices&sort=relevance'
>>> from urllib2 import urlopen
>>> html = urlopen("http://stackoverflow.com/search?%s" % params).read()
>>> import re
>>> links = re.findall(r'<h3><a href="([^"]*)" class="answer-title">([^<]*)</a></h3>', html)
>>> links
[('/questions/5119/what-are-the-best-rss-feeds-for-programmersdevelopers#5150', 'What are the best RSS feeds for programmers/developers?'), ('/questions/3088/best-ways-to-teach-a-beginner-to-program#13185', 'Best ways to teach a beginner to program?'), ('/questions/13678/textual-versus-graphical-programming-languages#13886', 'Textual versus Graphical Programming Languages'), ('/questions/58968/what-defines-pythonian-or-pythonic#59877', 'What defines &#8220;pythonian&#8221; or &#8220;pythonic&#8221;?'), ('/questions/592/cxoracle-how-do-i-access-oracle-from-python#62392', 'cx_Oracle - How do I access Oracle from Python? '), ('/questions/7170/recommendation-for-straight-forward-python-frameworks#83608', 'Recommendation for straight-forward python frameworks'), ('/questions/100732/why-is-if-not-someobj-better-than-if-someobj-none-in-python#100903', 'Why is if not someobj: better than if someobj == None: in Python?'), ('/questions/132734/presentations-on-switching-from-perl-to-python#134006', 'Presentations on switching from Perl to Python'), ('/questions/136977/after-c-python-or-java#138442', 'After C++ - Python or Java?')]
>>> from urlparse import urljoin
>>> links = [(urljoin('http://stackoverflow.com/', url), title) for url,title in links]
>>> links
[('http://stackoverflow.com/questions/5119/what-are-the-best-rss-feeds-for-programmersdevelopers#5150', 'What are the best RSS feeds for programmers/developers?'), ('https://dev59.com/oHVD5IYBdhLWcg3wXaYd 'Best ways to teach a beginner to program?'), ('https://dev59.com/AnVD5IYBdhLWcg3wVKEb 'Textual versus Graphical Programming Languages'), ('http://stackoverflow.com/questions/58968/what-defines-pythonian-or-pythonic#59877', 'What defines &#8220;pythonian&#8221; or &#8220;pythonic&#8221;?'), ('http://stackoverflow.com/questions/592/cxoracle-how-do-i-access-oracle-from-python#62392', 'cx_Oracle - How do I access Oracle from Python? '), ('http://stackoverflow.com/questions/7170/recommendation-for-straight-forward-python-frameworks#83608', 'Recommendation for straight-forward python frameworks'), ('https://dev59.com/7HVD5IYBdhLWcg3wE3No 'Why is if not someobj: better than if someobj == None: in Python?'), ('http://stackoverflow.com/questions/132734/presentations-on-switching-from-perl-to-python#134006', 'Presentations on switching from Perl to Python'), ('http://stackoverflow.com/questions/136977/after-c-python-or-java#138442', 'After C++ - Python or Java?')]

转换为函数应该很轻松。
编辑：好吧，我来做...
def get_stackoverflow(query):
    import urllib, urllib2, re, urlparse
    params = urllib.urlencode({'q': query, 'sort': 'relevance'})
    html = urllib2.urlopen("http://stackoverflow.com/search?%s" % params).read()
    links = re.findall(r'<h3><a href="([^"]*)" class="answer-title">([^<]*)</a></h3>', html)
    links = [(urlparse.urljoin('http://stackoverflow.com/', url), title) for url,title in links]

    return links
5
由于Stackoverflow已经具备此功能，您只需要获取搜索结果页面的内容并抓取所需信息。以下是按相关性搜索的URL：

https://stackoverflow.com/search?q=python+best+practices&sort=relevance

如果您查看源代码，您会发现每个问题所需的信息都在以下类似行中：
<h3><a href="/questions/5119/what-are-the-best-rss-feeds-for-programmersdevelopers#5150" class="answer-title">What are the best RSS feeds for programmers/developers?</a></h3>

所以，您可以通过使用正则表达式搜索该形式的字符串来获取前十个。

2
1

你可以从有效的HTTP请求中抓取返回的HTML。但这会导致不好的业力，并且失去享受良好睡眠的能力。

0

我会使用Pycurl将搜索术语连接到查询URI上。

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